Omit A Part Of Text File

On kali, how do i split a 15.7gb text file into 3 parts ? Also when i split the text file i don't want words to be incomplete from the split. Please help on how to exactly do it. Writing the exact commands to my specific situation would help me out a lot. Thanks in advance.

Hi
I want sort below text similar picture.
how we can doing that with command on Linux?

please see the attached.



sort.txt

in a linux mint installation should there be a /run directory?

Code:

 > ls /run
acpid.pid               initramfs           samba
acpid.socket            kerneloops.pid      sdp
alsa                    lock                sendsigs.omit.d
apache2                 mdm.pid             shm
avahi-daemon            mlocate.daily.lock  systemd
console                 motd.dynamic        tor
ConsoleKit              mount               udev
console-kit-daemon.pid  mysqld              udisks2
crond.pid               network             upstart-file-bridge.pid
crond.reboot            NetworkManager      upstart-socket-bridge.pid
cups                    plymouth            upstart-udev-bridge.pid
dbus                    pm-utils            user
dirmngr                 pppconfig           utmp
dirmngr.pid             resolvconf
gdm_socket              rsyslogd.pid

Hello--

I'm trying to locate a file or a command line in a file on my hard drive. I am running Ubuntu 12.05.4 linux. Is there a grep command that will search the whole tree from root down to all the sub-directories?

Thank You.

HI,

I am a newbie to Linux and am trying to create a pipe file with the below command:

mkfifo pone

Now I am trying to write data to the file with the following command on the command prompt:

echo asdadsasdasdasdasdasd >./pone

But after i enter this command- the screen hangs up and doesnt proceed ahead.
Same thing happened when I tried writing using:
gedit pone


Can anyone help me resolve this issue?

ok so im using osx 10.6.8 but i have something with linux on it somewhere I can try this on if that is the problem

I am attempting to take certain parts out of a html file I have figured out how to write a regular expression to specify this data I want to delete using the search funciton in the text editor TextWrangler:

(?<=<div id="right_col">)[\s\S]*(?=</body>)

This works in text wrangler but when I try to use it with sed it gives me errors like this one:

sed: 1: "(?<=<div id="right_col" ...": invalid command code (

I know to use -e to avoid problems with the unix version OSX is based on. The sed is a bit different because its based on an older unix variant but i did that and its still giving me an error. I assume there is something basic I am missing about formatting your regular expression for using with commandline and what characters you can use. I bet it has something to do with the backslashes or the round brackets. normally I would just keep searching till I find the answer but I am bored of this problem. I need to think about something else for awhile. maybe in the meantime someone else can chime in and help me out.

hi,

I am newbie in Linux shell scripting.Can anybody help me to check the presence of file identified by variable in Shell scripting?

For example: I am reading the content of a file using while command as below:
"while read -r line
do
code block
done < file_name"

Now in this case every line in file gets stored in the variable 'line' one by one.Problem here is every line in the file is nothing but the file_path of another file say xyz.txt and I am checking presence of this xyz.txt file using below command:
if [-f $line]
as 'line' is the variable which stores file path of xyz.txt but it is not working. It is unable to check the presence of this xyz.txt file as i am addressing it with the variable 'line'.

Please help me.Thanks in advance.

I am trying to process some .csv files with Linux as follows:

Some fields have data with newline characters embedded, like so:

"Bob Smith
531 Pennsylvania Avenue
Washington, DC"

(I verified the existence of the " via Wordpad. The file is too large to easily edit in Wordpad to get all the data for each row on a single line).

what linux command would I use on the files to get the data in each cell on one line?

I have tried:

1. awk -v RS="" '{gsub (/\n/,"")}1' file > newfile

but the cell data was still being read in as if "531 Pennsylvania Avenue" was a brand new row in the CSV file.

2. Command 1 followed by awk -v RS="" '{gsub (/\r/,"")}1' newfile > finalFile

but that resulted in all of the data in the file being put onto a single line.

3. awk -v RS="" '{gsub (/\r\n/,"")}1' file > newFile

But that result was the same as attempt number 2.

How can I preprocess the file so that:

"Bob Smith
531 Pennsylvania Avenue
Washington, DC"

is read as a single field on a single line as part of the row it should be associated with, like

"Bob Smith 531 Pennsylvania Avenue Washington, DC"

Ubuntu 12.04

I installed updates, which included a new kernel. I went to remove one of the older kernels and got:

Code:

jnojr@DEV:~$ sudo apt-get purge linux-image-3.13.0-46-generic
Reading package lists... Done
Building dependency tree       
Reading state information... Done
The following packages were automatically installed and are no longer required:
  linux-headers-3.13.0-46-generic gir1.2-ubuntuoneui-3.0 wireless-regdb iw
  linux-headers-3.13.0-46 crda linux-headers-3.5.0-23-generic lesstif2
  linux-headers-3.5.0-23 libubuntuoneui-3.0-1 thunderbird-globalmenu
Use 'apt-get autoremove' to remove them.
The following packages will be REMOVED:
  linux-image-3.13.0-46-generic*
0 upgraded, 0 newly installed, 1 to remove and 0 not upgraded.
After this operation, 197 MB disk space will be freed.
Do you want to continue [Y/n]? y
(Reading database ... 340656 files and directories currently installed.)
Removing linux-image-3.13.0-46-generic ...
Examining /etc/kernel/postrm.d .
run-parts: executing /etc/kernel/postrm.d/initramfs-tools 3.13.0-46-generic /boot/vmlinuz-3.13.0-46-generic
update-initramfs: Deleting /boot/initrd.img-3.13.0-46-generic
run-parts: executing /etc/kernel/postrm.d/zz-update-grub 3.13.0-46-generic /boot/vmlinuz-3.13.0-46-generic
Generating grub.cfg ...
Found linux image: /boot/vmlinuz-3.13.0-51-generic
Found initrd image: /boot/initrd.img-3.13.0-51-generic
Found linux image: /boot/vmlinuz-3.13.0-49-generic
Found initrd image: /boot/initrd.img-3.13.0-49-generic
Found linux image: /boot/vmlinuz-3.13.0-48-generic
Found initrd image: /boot/initrd.img-3.13.0-48-generic
Found Windows Vista (loader) on /dev/sda1
Found CentOS release 6.6 (Final) on /dev/sdb1
Found linux image: /boot/vmlinuz-3.13.0-51-generic
Found initrd image: /boot/initrd.img-3.13.0-51-generic
Found linux image: /boot/vmlinuz-3.13.0-49-generic
Found initrd image: /boot/initrd.img-3.13.0-49-generic
Found linux image: /boot/vmlinuz-3.13.0-48-generic
Found initrd image: /boot/initrd.img-3.13.0-48-generic
Found Windows Vista (loader) on /dev/sda1
Found CentOS release 6.6 (Final) on /dev/sdb1
Found memtest86+ image: /boot/memtest86+.bin
error: syntax error.
error: Incorrect command.
error: syntax error.
error: Incorrect command.
error: syntax error.
error: line no: 146
Syntax errors are detected in generated GRUB config file.
Ensure that there are no errors in /etc/default/grub
and /etc/grub.d/* files or please file a bug report with
/boot/grub/grub.cfg.new file attached.
done
Purging configuration files for linux-image-3.13.0-46-generic ...
Examining /etc/kernel/postrm.d .
run-parts: executing /etc/kernel/postrm.d/initramfs-tools 3.13.0-46-generic /boot/vmlinuz-3.13.0-46-generic
run-parts: executing /etc/kernel/postrm.d/zz-update-grub 3.13.0-46-generic /boot/vmlinuz-3.13.0-46-generic

I have no idea how I'd "ensure there are no errors" in the /etc/grub related files... I have no idea what's supposed to be there. Looking at the line it's complaining about in /boot/grub/grub.cfg.new doesn't tell me anything. How do i find out what it's unhappy about?

hey guys,

Let's say I want to find out which log files have related ntp information in them. I use cat and grep to search through the files in /var/log and then export that to a file. this is the command...

# cat /var/log/* | grep ntp > /home/log.txt

The file created from this command will not include the directories the log entries are apart of. Why not? For example, if you do this same command without exporting to the /home/log.txt file it will show you in stdout which directory each log entry is in. Hope I'm making sense here. My question is, is there a clever way to export to a file in a way so that the file created is structured exactly like the stdout of the command below?

# cat /var/log/* | grep ntp