Help On Explaination Of Shell Script

Ok yes this is a homework assignment BUT I am NOT looking to have the answers given to me. I am in the 6th week of my first Linux class ever and we are in our few weeks of beginning scripting. I have some ideas of what to do or where to start but not many and no one to bounce any ideas off...we are using UNIX Bash shell so any others I have no clue. The scenario is that I need a script that searches all my users home directories for bad words. I need the script to report to the screen certain info like username and word found and path. It should ask a user if it is good or bad and if bad be put into a file of list of bad file names, if good remove from list and no longer flagged by the script. What I have so far is wanting to somehow do a loop. I do know that if I do a grep -r -e kill -e steal /home/* I get a list of what I need. I also know that the list is separated by delimiters which I can pipe to get a variable for the things I need. I also know that I can put it to a file with a > filename.txt

What I have no clue is how to start a loop that would do this...

for each line in filename.txt
UNAME=...
LOC=...
TXT=...
echo "Username: $UNAME, Line with bad word found: $TXT, and Path and file name: $LOC. Is this a BAD file? (Y)"
Read YORN

if ["$YORN" = "Y" ]; then
>> (line of text from grep) badfiles.txt
fi

Next or whatever goes there...sorry if this is crazy I just really need some direction. I am trying to learn so please don't give me the answer...that will do nothing for me and I will not be able to explain the code I came up with.

can some1 please tell me ....i am writing script to display type of file....and i m not able to get what "filename##*\." means?....please be brief in your explanation..thank you
the program is like:
for filename in$(ls)
do
ext=${filename##*\.}
case '$ext' in

Hi!
I wrote a script shell about changing IP of the httpd.conf from text file and saving a new httpd.conf file for all IPs in the text file. The code is below, Im using mremote on windows (RHEL Release 5.7), and getting this error:
./script1.sh: line 19: syntax error: unexpected end of file

Please help me about that error. Thanks!

(ps: line 19 is the last line in the code => done < "$filename" )

#!/bin/bash

DATE='date +%Y%m%d_%H:%M:%S'
NAME=httpd_ip_change
EXTENSION=conf
max=10

filename="$1"
while read -r line

for ((i=2; i<=$max; ++i ))

do
touch $NAME$i.$EXTENSION.$DATE

sed "s/<VirtualHost 10.11.92.81:80>/$line/g" ./httpd.conf > $NAME$i.$EXTENSION.$DATE

done < "$filename"

I am not sure how to ask this, sorry.

if I had a code like this

Code:

# grep -a ": " md5list.txt | cut -f2,3 -d

How can I run the command basename for each line of the output?

basename {(grep -a ": " md5list.txt | cut -f2,3 -d )}


EDIT: A little more clarity on what im doing:
I didn't realize that 'md5sums' was a link to a nice formatted page. So I copied all packages here and put them into a text file. I decided to write a script that put all of these in that format.

So basically, even though I have already ran the md5sum -c 'md5sum-list' I still want to finish this small project because I am learning a ton.

Hi

I'm focusing on getting my head around interactive v non-interactive shells, both non-login and login. Basically what scripts are run and how local and global variables behave.

I'm pretty much there except for 'non-interactive login shells'. I understand that 'non-interactive' shells are started when a script is run. However, if I start my script with #!/bin/bash --login, then a 'non-interactive login' shell will be started.

In my mind I would have expected this to be the same as logging in from scratch, albeit without a user\password prompt. In this case I would have thought that any exported variables from the parent shell would be blown away. This doesn't appear to be the case. The 'non-interactive login' shell appears to inherit the environment of its parent 'interactive' shell.

Can anyone explain the purpose of a 'non-interactive login' shell and how they behave in this regard.

Hope this makes sense.

Cheers

Mike

Hi,
I am looking for a simple shell script that allows for sftp to be run from the server to another server (Windows). I would like the script to be passed parameters suchas destination server, Id, password, Directory structure/folder name, file name etc...
Need some help to know how to start with and it would be great if someone help me with any sample sftp shell script

Is there a way to have a script called source, that can be run without the full path?

Ex:
When I run:
export PATH=/home/user:$PATH
source

I get:
Code:

$ source
bash: source: filename argument required
source: usage: source filename [arguments]

However I want it to run my script called source:
Code:

$ cat source 
#!/bin/bash
echo "Hello World"

Is there way to override a shell builtin in the PATH var or some other way?

Hi All,

I have two scripts, the aim of these two scripts is, to check whether a particular script is running or not, if it wont runs, then throw a mail.

How i Achieved this output is, I wrote first script.

I created an infinite while loop which performs below steps

1. It creates a touch file
2. Triggers the script which needs to be monitored if its working or not.
3. Removes the touch file.

If the second step fails, then the remove file command will not happen and the script will stuck there itself.

I created an another script which checks the creation time of the touch file and if it is more than ten minutes, it means the second step in the first script is hanged, which also means that particular script is not working.

So if the creation time is more than 2 minutes the second script will throw a mail.

Below are the two scripts.

Code:

#!/bin/ksh



userid="chansd"

filename="/apps/log/check.txt"

while true ;do
touch $filename
pass=`/apps/eDMZ/call_st.ksh $userid`
sleep 20
rm $filename
done

Below script checks the file creation time and throws email if it is older than 2 minutes
Code:

#!/bin/ksh


filename="/apps/log/check.txt"

if [ -f "${filename}" ]
then
if test "`find $filename -mmin +2`"
then
echo "script is not working ! Please act on it" | mail -s "Script  is not working" Example@mail.com
fi


else

        exit 1

fi

What im going to do is

1. I am going to run the first script in background so it runs forever.
2. I am going to run the second script in cron forevry 5 mins to check the file creation time.

3. So if the first script hangs . I will kill the process using process id and after the issue resolves with the inner script, I will run the main script again.

I am new to Linux, Please let me know if this approach will work as expected.

Hi Everyone,

I need some help on my bash script, I'm trying to rename a certain line in a file which might be 1 or more.

IDXCOUNT=`grep -c 'index .* on ' $FILENAME`;

for n in $(eval echo {1..$IDXCOUNT});
do
timestamp=$(date +"%s");
echo "Renaming index idx_$timestamp..";
if [ $n -eq 1 ]; then
sed -i "0,/^index [^)]* on /s/index idx_$timestamp on /" $FILENAME;

My problem is, if the sed target is 2 or more it will generate an idx_$timestamp that will cause duplicate index value when the script finish. My goal is to have the script recognize that when there are multiple index in the file, it will try to rename it one by one.

I'm new to bash so I'm not sure if I explained my issue well but I will appreciate any help!!

Thanks!

Hello,
I'm working on a shell script that needs to read the a file (file1) a batch (read 2000 lines at a time) and then write those lines to seperate file which I'm using to run ldapmodify command. I need to check some other file size and once this file less than 200kb, i would need to run second batch and so on until file1 is empty.
Quote:
#!/bin/bash
set -x
filesize=200
server=10.11.xxx.xx
filename=fileimport.txt
taofile1=687686.txt
taofile=/var/opt/$taofile1

stty -echo
echo -n "Enter password: "
read passwd
stty echo
context="cn=user1,ou=org1,ou=org2,o=org"
if [[ -s "$filename" ]];then
for lines in $filename
do
head -99997 fileimport.txt >> ldapreadd.ldif && sed -i '1,+99996d' fileimport.txt
if [ -s ldapreadd.ldif ];then
ldapmodify -h $server -p 389 -D $context -w $passwd -v -x -f ldapreadd.ldif &> /dev/null
echo "LDIF script is running. Please wait..."
sleep 60
if [ -f "$taofile" ];then
taofilesize=`stat -c %s ${taofile}`
# if [ "$taofilesize" -ge 200 ];then
while [ `stat -c %s ${taofile}` -ge 200 ]
do
echo " Driver is processing LDIF file. Please wait..."
sleep 60
done
fi
rm -rf ldapreadd.ldif
fi
done
else
echo "$filename file is empty. Exiting script..."
exit
fi

I have 2 issues here. first one script is not reading exact lines as specified. Some times its reading more lines some times less lines. Second issues once it run the first batch, script is exiting. Please advise.