Equivalent Command For "time -v" In Centos

I'm currently using the command below, to output the memory usage of a debian system in bash scripts.

Code:

memusage=$(memusage=$(/usr/bin/free | grep Mem | awk '{print $3/$2 * 100.0 "%"}' | cut -d "%" -f1);echo "$(printf "%0.0f\n" $memusage)") && echo Memory Usage is $memusage

Being new to Linux though, I just found out that Linux takes up a lof of memory and puts it in cached.

Code:

root@Client1:~# free -m
             total       used       free     shared    buffers     cached
Mem:           927        799        128          0         15        754
-/+ buffers/cache:         28        898
Swap:           99          0         99

So the first command will actually output that the memory usage is 87%, when in reality is not. Its actually thinking that the memory usage is high because its also counting the cached memory, as used memory.

How can I modify the first command not to consider cached memory, as used memory?

Thanks

I am novice at linux...I installed VMware work station and then install centos 6.4. Now I followed this tutorial to configure DHCP Server on my OS http://tecadmin.net/configuring-dhcp...centos-redhat/
but when start dhcp I see this : Starting dhcpd:[FAILED]
This is my /etc/dhcp/dhcpd.conf

option domain-name "center.local";
option domain-name-servers master.center.local;
default-lease-time 600;
max-lease-time 7200;
authoritative;
log-facility local7;
subnet 192.168.1.0 netmask 255.255.255.0 {
option routers 192.168.1.1;
option subnet-mask 255.255.255.0;
option domain-search "center.local";
option domain-name-servers 192.168.1.100;
option time-offset -18000; # Eastern Standard Time
range 192.168.1.100 192.168.1.120;
}

host station1 {
option host-name "centos-1.center.local";
hardware ethernet 00:11:1A:2B:3C:AB;
fixed-address 192.168.1.101;
}

so what is wrong?Any suggestion?
Thanks for your help and sorry for my bad English grammar

Hi Experts:

I'm new to Linux,recently i was confused with the words as below:

"To achieve sharing,the process A mmaps the executable file of process B into into the virtual address space of process A. As the Linux loader maps the executable files into the process when executing them,the two processes share the memory image of the mapped file"

questions:
1,What are the "executable files",are they ELF files?
2,How to do "mmaps"？if process A and process B share the same code segment, ,where is process A's own code segment?


Thank you in advance.

I am using the following two commands to output CPU and RAM usage on a Linux machine.

Code:

/bin/grep 'cpu ' /proc/stat | awk '{usage=($2+$4)*100/($2+$4+$5)} END {print usage "%"}'

/usr/bin/free | grep Mem | awk '{print $3/$2 * 100.0 "%"}'

My problem is that the output is like this

Quote:
5.33672%
13.9723%
Is there a way to output a single number? For example

Quote:
5
13
Thank you

hello everyone.,
i am using linux Centos 6 machine, i have downloaded "back in time" through command line.
but i dont know how to install "back in time" from the command line.
i found some commands but that for UBUNTU and not running on Centos 6, giving error.
so , without GUI. can be possible to install and use it?????

thanks in advance..

Hi guys,

I am looking to write a script where I need to process many sets of transactions.
I want to process the set if $ 1 == "01" field $5 = "W", and $ 1 == "07" field $3 = "YY" otherwise copy set to output.

Example of the input file:

Code:

01 08 77 78  W  9890
02 08 66 68 0 8554
07 08  YY  85 9 7545
01 08 99 87 X 8787
04 09 85 85 4 8758
09 87 88 78 7 6584
10 84 ZZ 99 8 9887

A new set is always starting with $1 == "01".
Script should only process first set because its 5th value is "W" and put "MATCHED" in the end.
and copy the unmatched set "X" as it is to output.

Code:

Example of output file:
 01 08 77 78 W 9890
02 08 66 68 0 8554
07 08 YY 85 9 7545
MATCHED 
 01 08 99 87 X 8787
04 09 85 85 4 8758
09 87 88 78 7 6584
10 84 ZZ 99 8 9887 

and so on..
thanks for your help

i need to complete this exercise but my code has some issues
HERE is the PRoblem:
Create a script that can accept ANY amount of numbers from the command line. Process the numbers one at a time, where numbers greater than 10 print “large”, numbers less than or equal to 10 print “small”
E.g. process 5 10 15 would print
small
small
large

and here is my code so far
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi

any help would be greatly appreciated

hello all..
I am using Centos 6. Is there any way to run or start "back in time" and "team viewer" from the command line??
plzz help me.. its an urgent..
thanks in advance

I just download the below files and tried to install it to virtualbox .

CentOS-7.0-1406-x86_64-DVD
CentOS-7.0-1406-x86_64-Everything


When it is booted to the DVD , it pop the below messages .

============================================
Install CentOS 7
Test this media & install CentOS 7
Troubeshooting

Press Tab ...
============================================

I tried to select any option , but the screen become dark , it seems the installation process is stopped ,

I tried Centos 5.x , it works fine , but Centos 7 not work.

would advise what is wrong ? thanks

I have this question which give me a file.tar.gz which include a calculator file and want to extract and run it
in the output it wants to show
1)cpu avg usage
2)total time taken to run
3)memory and I/O usage
can anyone help???