Make Menuconfig: Do You Have To Run 'make' Every Time?

Hi everyone (i hope this is the right section)

Im trying to install the RT patch preempt_rt 3.18.9 im running Ubuntu 14.04 with kernel v 3.16

i installed the rt patch "patch-3.18.9-rt5.patch" and also a new kernel "3.18.9" i patched the patch file with

patch -p1 < patch-3.18.9.patch

but there is somthing i don't know about linking folders of old kernel and new kernel, i searched about it and found

rm -rf linux && ln -s /usr/src/linux-3.18.9 linux && cd /usr/src/linux

then

make oldconfig

then

make menuconfig

i selected Full preemptive kernel then

make

then this error

cc1: some warnings being treated as errors make[2]: * [kernel/locking/locktorture.o] Error 1 make[1]: * [kernel/locking] Error 2 make: *** [kernel] Error 2


So..... Any help?? can someone walk me through this

or any other real time patch, Thanx.. plzzzzzz

I have setup a dual boot system with Fedora 21 and Arch Linux. The problem is that Fedora doesn't see my encrypted Arch installation. The installations are on separate partitions and do not share anything apart from hard disk space. I have run the following commands as root in Fedora:

Code:

grub2-install /dev/sda

Code:

os-prober

Code:

grub2-mkconfig -o /boot/grub2/grub.cfg

When I rebooted, Fedora was the only OS entry showing in the GRUB menu.

There was a suggestion from one of the members of the Arch forums that I should write the entry myself into /etc/grub.d/40_custom and then re-build the grub configuration or take the Arch entry from Arch's /boot/grub/grub.cfg and just paste it into the 40_custom in Fedora and rebuild.

How do I boot from a live Arch USB stick into the installed Arch and do as stated above? How would it work? Thanks in advance for your replies.

System Info:

I have normal user in CentOS 7 whose name is "mostafa" (the name of the account).

I naturally have another user called root with all privileges. User "mostafa" is put into sudoers file, too.

The OS is installed in VmWare, so the system is all mine.

Problem:

Now I create a file with touch file.sh and put a command in it, but when I want to run it with Code:

sudo ./file.sh

, an error is shown that the command Code:

./file.sh

does not exist. But if I Code:

 sudo chmod 777 ./file.sh

then it gets run. My question is that, why should I use Code:

chmod 777

when I myself have created the file, and I am in sudoers.

Can anyone explain me why shuold I still use Code:

sudo chmod 777

when the creator of the file is me.

Hi,
I am crosscompiling u-boot for the beaglebone black and I have a problem that I don't understand.

I have installed correctly the linaro cross-compile tools and export the environment variable CC as:
export CC=/path_to_linaro_arm_cross_compiler/bin/arm-linux-gnueabihf-

And if I type in the terminal:
${CC}gcc --version

I see the linaro's compiler version, so all seems to be ok.

But, when I try to create the config file for the BBB with the command:
make ARCH=arm CROSS_COMPILE=${CC} am335x_boneblack_defconfig

It complains with the message: "/bin/sh: 1: cc: not found"

Am I missing something?

Hi, i know this could seems like a "simple" question but after a lot fo try i can't seems to make it works, i am stuck on this. I am working on a sbc6000x board, linux 2.6.24, an embedded system.

I am working on a pretty nice project which when called like this run perfectly :
Code:

cd /bin
./apps

(/bin/apps don't works, it must be ./apps from the directory)

After searching a little about the startup i learned about rc.local and created it in /etc/init.d, rc.local look like this :

Code:

#!bin/sh
# /etc/rc.d/rc.local: Local system initialization script.
#

cd /bin
./apps
cd

Sadly it seems it is never called. I was thinking about maybe add cd /bin, /.apps to the end of the etc/profile but i don't know if profile can run command aside from simple scripts call.

Does anyone has an idea on why this don't work or on how i could do this ?

I have CentOS 7 64 bit. I have installed open-vm-tools on it.
I have installed vmplayer using
Code:

./VMware-Player-6.0.1-1379776.x86_64.bundle

Now when I try to open vmplayer on it, it does not load 'Virtual Network Device'
and shows error in terminal
Code:

Failed to build vmnet.  Failed to execute the build command.

When I check status of vmware, it shows
Code:

Module vmnet not loaded

If I try to run
Code:

vmware-modconfig --console --install-all

It gives me following error.
Code:

make: Leaving directory `/tmp/modconfig-2NfFeS/vmnet-only'
Unable to install all modules.

I am not able to open VMplayer, please help me to open it.

Thanks

--Kind Regards
Sam

Hi ,

Please explain what the below command means ..


Code:

if grep -c -i Y $INIFILE > /dev/null

I know what is the use of grep, it is used for finding a character or string in a file. But i could not understand the above form of grep command.

I am new to linux so this might be a simple question, but please throw some light on it.


Edited

And also please explain why they are creating a file in null in the below command

Code:

cat /dev/null > $DATA_DIR/$DATAFILE

Hi, I am trying to install a smartcard reader driver onto my ubuntu machine. I am not able run the make file.

The output of makefile is as follows:
Code:

amit@ubuntu:~/Downloads/Linux Driver/rts_pstor$ sudo make
sed "s/RTSX_MK_TIME/`date +%y.%m.%d.%H.%M`/" timestamp.in > timestamp.h
cp -f ./define.release ./define.h
make -C /lib/modules/3.16.0-36-generic/build SUBDIRS=/home/amit/Downloads/Linux Driver/rts_pstor modules
make[1]: Entering directory `/usr/src/linux-headers-3.16.0-36-generic'
arch/x86/Makefile:136: CONFIG_X86_X32 enabled but no binutils support
Makefile:652: Cannot use CONFIG_CC_STACKPROTECTOR_REGULAR: -fstack-protector not supported by compiler
make[1]: *** No rule to make target `Driver/rts_pstor'.  Stop.
make[1]: Leaving directory `/usr/src/linux-headers-3.16.0-36-generic'
make: *** [default] Error 2
amit@ubuntu:~/Downloads/Linux Driver/rts_pstor$

The make file for this driver is as follows:

Code:

TARGET_MODULE := rts_pstor

EXTRA_CFLAGS := -Idrivers/scsi 

obj-m += $(TARGET_MODULE).o

$(TARGET_MODULE)-objs := rtsx.o rtsx_chip.o rtsx_transport.o rtsx_scsi.o rtsx_card.o \
			 general.o sd.o xd.o ms.o spi.o

default:
	sed "s/RTSX_MK_TIME/`date +%y.%m.%d.%H.%M`/" timestamp.in > timestamp.h
	cp -f ./define.release ./define.h
	make -C /lib/modules/$(shell uname -r)/build SUBDIRS=$(shell pwd) modules
debug:
	sed "s/RTSX_MK_TIME/`date +%y.%m.%d.%H.%M`/" timestamp.in > timestamp.h
	cp -f ./define.debug ./define.h
	make -C /lib/modules/$(shell uname -r)/build SUBDIRS=$(shell pwd) modules
install:
	cp $(TARGET_MODULE).ko /lib/modules/$(shell uname -r)/kernel/drivers/scsi -f
clean:
	rm -f *.o *.ko
	rm -f $(TARGET_MODULE).mod.c

Please let me know any of your comments.

Thanks,
Amit

There's something really weird happening with permissions on a directory in linux. I have the directory /dir

Code:

ls -ld /dir
drwxrwxrwx. 2 root root 4096 Jan  8 00:06 dir
chmod 2777 /dir [this sets the setgid bit on]
ls -ld /dir
drwxrwsrwx. 2 root root 4096 Jan  8 00:06 /dir

And this is what I expect it to do.
However, when I change it to setid (WITHOUT setgid), it simply doesn't work. Instead of overwriting, it cumulates:
Code:

chmod 4777 /dir [for setting setuid bit on]
drwsrwsrwx. 2 root root 4096 Jan  8 00:06 /dir

As you can see, the setgid bit is still on together with the setuid! However, if I run:
Code:

chmod -s /dir

then the file has a 0777 permission.

And then again, if I change its permission to 4777 (so setuid):
Code:

chmod 4777 /dir
drwsrwxrwx. 2 root root 4096 Jan  8 00:06 /dir

it acts normally. So the same chmod 4777 acts differently in two different contexts.

I really can't understand it. Basically, I cannot get rid of the setuid/setgid through binary permissions. The sticky bit works fine. Changing from 1777 to 0777 adds and removes "t" respectively. What am I to make of all this? This behaviour makes no sense to make especially given that we can change the permissions to 6777 (setuid + setgid).

Hi all,

Been reading on stdin, stdout and stderr and encounter 2 questions, hope gurus here can advise.

0 = stdin
1 = stdout
2 = stderr

Code:

Sun Dec 21 03:53:42 SGT 2014 > cat test5.sh
#!/bin/bash

echo "Please enter value for name :"
read name
echo "Your name is $name."

echo "Next echo will be a syntax error"
ehco

Code:

Sun Dec 21 03:53:46 SGT 2014 > test5.sh 1> output.txt 2> error.txt
Noob

Sun Dec 21 03:54:56 SGT 2014 > cat output.txt
Please enter value for name :
Your name is Noob.
Next echo will be a syntax error

Sun Dec 21 03:55:23 SGT 2014 > cat error.txt
/home/alan/scripts/test5.sh: line 8: ehco: command not found
Sun Dec 21 03:55:26 SGT 2014 >

Which so far all is good and the correct way to output everything including error to a single file is

Code:

Sun Dec 21 03:59:14 SGT 2014 > test5.sh > output.txt 2>&1

Q1) How is a command being interpreted in linux , the sequence in which it is interpreted ? from left to right ? right to left ?

Shouldn't it be

Code:

test5.sh 2>&1 1>output.txt 
or 
test5.sh 2>&1>output.txt ?

Regards,
Noob