How Can I Get Shell To Read Special Characters As Strings? Such As $ Or !

I am using a shell script named by test.sh, for example containing
Code:

address="$PWD"
echo "$address"

.
If I put it in folder temp1, and run test.sh, then it will give me the address of the current directory. But if I am now in folder temp2, and I want to run test.sh, I always need to copy test.sh to folder temp2, and then run it. Is there a way that I can run test.sh without copying it? I am not root user.

I'm trying to loop through a query in SQLDeveloper by passing the query a different Period and I'm having a problem getting the syntax correct.

Individually the following works correctly on its own:

Code:

#!/bin/bash
 for i in `seq -f "%02g" 1 5`;
    do
    echo $i
 done

$ ./test.sh
1
2
3
4
5

the following also executes correctly:

Quote:
sqlplus table1/$userpass@Mytable <<EOF
@./sqlcode.sql $i
EOF
but when I try to wrap the loop around my sqlplus command

Code:

#! /bin/sh
userpass=read
for i in `seq -f "%01g" 1 3`;
  do
        sqlplus -S  table1/$userpass@Mytable <<EOF
        @./sqlcode.sql $i
        EOF
done

I get the following error:

./test.sh: line 13: syntax error: unexpected end of file

Does anyone have any ideas on what's going on?

Hi All,
We have some shell scripts which will send emails about backup, alerts etc using mail command. Example.
Code:

echo "Test Mail" | mail -s "Test" me@mydomain.com

I guess the above command just connect port number 25 of our mail server even if we do not define any port number. Now I would like add smtp port number as 587 in all of the bash scripts. I googled for this but could not get whatever I am expecting. So expecting your kind reply to define smtp port number as 587 in all of the bash scripts.

Thanks in advance.

Code:

PREFIX=192.168.1
OCTET=1
while [ $OCTET -lt "255" ]; do
    echo -en "Pinging ${PREFIX}.${OCTET}..."
    ping -c1 -w1 ${PREFIX}.${OCTET} > /dev/null 2>&1
    if [ "$?" -eq "0" ]; then
       echo "OK"
    else
       echo "Failed"
    fi
    let OCTET=$OCTET+1
done

My question is, in the penultimate line, why is it OCTET, and not $OCTET, with a dollar before it, meaning, the variable?

What if it were written:
Code:

let $OCTET=$OCTET+1

Like in C++ (I think) or Python or whatever?

Hi all,

Been reading on stdin, stdout and stderr and encounter 2 questions, hope gurus here can advise.

0 = stdin
1 = stdout
2 = stderr

Code:

Sun Dec 21 03:53:42 SGT 2014 > cat test5.sh
#!/bin/bash

echo "Please enter value for name :"
read name
echo "Your name is $name."

echo "Next echo will be a syntax error"
ehco

Code:

Sun Dec 21 03:53:46 SGT 2014 > test5.sh 1> output.txt 2> error.txt
Noob

Sun Dec 21 03:54:56 SGT 2014 > cat output.txt
Please enter value for name :
Your name is Noob.
Next echo will be a syntax error

Sun Dec 21 03:55:23 SGT 2014 > cat error.txt
/home/alan/scripts/test5.sh: line 8: ehco: command not found
Sun Dec 21 03:55:26 SGT 2014 >

Which so far all is good and the correct way to output everything including error to a single file is

Code:

Sun Dec 21 03:59:14 SGT 2014 > test5.sh > output.txt 2>&1

Q1) How is a command being interpreted in linux , the sequence in which it is interpreted ? from left to right ? right to left ?

Shouldn't it be

Code:

test5.sh 2>&1 1>output.txt 
or 
test5.sh 2>&1>output.txt ?

Regards,
Noob

Hi Guys,
i have this Code:

uid=0(root) gid=0(root)

i would like to have the word "root" only from the first field, and later from the second field

i use the command
Code:

[root@v1-6 ~]# cat test-uid |cut -d"(" -f1
brms2
uid=0

[root@v1-6 ~]# cat test-uid |cut -d")" -f1
brms2
uid=0(root

it cut the word after the -d, how can i make it to cut the word BEFORE the -d

expected should be:
cut -d"(" -f1
root)

then i can proceed to eliminate the ) later on.
hope this is not confusing you guys

Thanks,

Hi, I know that it is possible to get the last background pid using the $! command, however when I use it in my QT application I got a wrong result. Below follows an example where this procedure works
Code:

[linux@localhost ~]$ (sleep 6 && echo "A test") &
[1] 3312
[linux@localhost ~]$ echo $!
3312
[linux@localhost ~]$ A test

Now my Qt application, where I got a wrong result:
Code:

./dbsync &>/dev/null &
[1] 5047
[linux@localhost comm5]$ echo $!
5047

but using the ps command it is possible to verify that the pid related to the right process is not the 5047 but 5050.
Generally it is the process that comes with the command Code:

echo $!

added of two.

I use QCoreApplication in my program. I do not know if it has something to do with this error.

Any advice is welcome

Apologies. I've been out of Unix for 14 years, and the gears have rusted. Also, Unix has changed - enough similarities to memory that I'm pretty comfy though.

Glad to see lots of info available via google. However changes are going to take getting used to. Have set up a testbed of 3 nearly identical machines, hoping to make an (at home) private network where I can automate installs and set-ups using NIS and NFS (Similar to work I once did).

Have found useful scripts interspersed with comments, would like to copy and paste them to a bash script that:

Reads the line.
Echos the line.
Reads the reply.
Executes what is typed.

Essentially, by making myself type (or copy & paste) the commands I think I'll become familiar.

Figured I'd use a spreadsheet, select the file, and paste into column B of the spreadsheet. In column A I'd paste:

echo "

and in column C I'd paste:

"

Then I'd cut and paste into a text document, insert the lines:

read A
$A

behind every command necessary to the actual task.

Figured I'd have to escape the ' and ".

Ran a test (test.bash):

#!/bin/bash
for i in `seq 1 10`;
do
echo "Enter a command:"
read A
echo "Trying $A"
$A
done

works fine when I type

ls -alg

but not so when I type

ls -alg | grep dwrx

so I'm wondering if someone has a suggestion?

Thanks for any ideas.

I have the following code to extract two dates using awk, which are then read into two awk variables new and old respectively.
Each dates on the html file pulled with curl request is in this format:
2015-04-06 09:40:37
And two are being extracted
However the strings are being split on white space within the date strings. I tried changing OFS to ',', but it was still splitting incorrectly.
Code:

read dateStrNew dateStrOld < <(curl -k -q "$curl_call" | html2text | gawk '/Newest Sequence/ { new=$3" "$4 }/Oldest Sequence/ \
 {old=$3" "$4}END {OFS=","; print new,old }')  //new = date, old = date

Both parts of the date are being assigned to each variable using $3 and $4, then the space needs to be added back in so that the string can be used afterwards with a date command.

I just can't work out what is wrong, any help would be very much appreciated! Thanks!

Hi guys,

i'm beginner with Unix, I tried my best, but I Really don't know how to finish it .

here's my problem : I have to do something like Student system - student's name | subjects | mark |credits.

after starting script it will ask you for Student's name, then which subject, then the mark will appear.

It's a homework, and I have my own idea how to solve it, but cannot finish it, i don't want complete solution, just a help!

Code:

#!/bin/bash
echo "Students name"
echo -n "Enter student's name: "
read name
echo
case $name in
Example1|Math) echo "C" ;;
Example2|Programming) echo "D" ;;
Example3|WWW) echo "A" ;;
Example4|Economie) echo "-" ;;
esac

I don't now how to bring together case with second things which is "enter subject".

I appreciate any help