Need Help Cat Multiple Files To One File

from the desk top i open documents file , i have multiple folders but no information Clearly what iam see is the background. how do i fix this perhaps i have deleted some thing wwhich has created the problem .

OPENING A FILE i receive multiple notification from OKULAR SAYING CANNOT OPEN FILE AND QUOTES FILES WHICH HAD BEEN DELETED .
ANY SUGGESTION ON HOW I CAN FIX THE DEFECTS .

Does anyone know a way to copy two files to multiple computers? I'm thinking of scp as the flavor of linux we're using does not include rdist.

I've read that scp can't copy multiple files, however maybe some scripting genius has figured out a way. Running two scripts (one for each file), is perfectly ok!

If anyone care to post very clear examples (i'm definitely not a programmer...) of scripts, etc, that would be great.

Thanks in advance to all those who can help!

Hi guys,

I have multiple .csv files with multiple columns/headings, set up essentially like this (obviously more info in the real thing)


Gene Location Ref Var Coverage Function
DMD chrX.... A G 198 exonic
SCN4A chr17.... T C 111 splicing

and so on...

How could I concatenate selected columns into an output file with strings seperated with a comma? eg DMD,A,G,exonic (similar to what you can do in excel). I would like to be able to do this for multiple files in a directory. It would be preferable if all the outputs could be compiled into one file as I'll use this for something else later.
The current protocol in our team is to concatenate each file individually with an excel macro and copy into a file, and it takes a very long time.

Thanks very much!!

I am trying to process some .csv files with Linux as follows:

Some fields have data with newline characters embedded, like so:

"Bob Smith
531 Pennsylvania Avenue
Washington, DC"

(I verified the existence of the " via Wordpad. The file is too large to easily edit in Wordpad to get all the data for each row on a single line).

what linux command would I use on the files to get the data in each cell on one line?

I have tried:

1. awk -v RS="" '{gsub (/\n/,"")}1' file > newfile

but the cell data was still being read in as if "531 Pennsylvania Avenue" was a brand new row in the CSV file.

2. Command 1 followed by awk -v RS="" '{gsub (/\r/,"")}1' newfile > finalFile

but that resulted in all of the data in the file being put onto a single line.

3. awk -v RS="" '{gsub (/\r\n/,"")}1' file > newFile

But that result was the same as attempt number 2.

How can I preprocess the file so that:

"Bob Smith
531 Pennsylvania Avenue
Washington, DC"

is read as a single field on a single line as part of the row it should be associated with, like

"Bob Smith 531 Pennsylvania Avenue Washington, DC"

hello all,

please help me with python ftplib. i was trying to copy files from my linux machine to a windows server using ftplib. everything was working good. but i'm only able to copy files from the same directory the script is. how do i copy files from a different directory? i always get "file not found error message". here's my code :

Code:

tester_name = str (socket.gethostname())
def upload(ftp, file):
    ext = os.path.splitext(file)[1]
    if ext in (".txt", ".htm", ".html"):
        ftp.storlines("STOR " + file, open(file))
    else:
        ftp.storbinary("STOR " + file, open(file, "rb"), 1024)



parse_source_path = ('/path/to/where/i/go/')
parse_source_file_list = os.listdir(parse_source_path)

ftp = ftplib.FTP("server_IP")
ftp.login("username", "pass")

folder_list = []

ftp.dir(folder_list.append)

if str(tester_name) not in str(folder_list) :
    ftp.mkd("%s"%tester_name)
    ftp.cwd("%s"%tester_name)
    for files in parse_source_file_list :
        print files
        upload(ftp, files)


else :
    print "later"

Hi all,

I'm trying to identify files that do not have matches for certain strings. FYI, these are files of DNA sequences and I'm trying to find those that are NOT sampled for any species by my group of interest (e.g., genes that are specific to that group of organisms).

I tried this code but it's actually yielding a list of files that DO match for my regexp.
Code:

for FILENAME in *.fas
do
grep -q -L ">PBAH" $FILENAME && grep -q -L ">SKOW" $FILENAME && grep -q -L ">CGRA" $FILENAME && echo $FILENAME
done

Basically I want to somehow go through and file files that do not contain ">PBAH" ">SKOW" or ">CGRA". Any assistance would be greatly appreciated!

Best,
Kevin

I would like to tar up some system logs with core files as a normal user through a script. However these core files are owned by root.

Of course I get "cannot read directory ...: Permission denied"

Is there a good way to grab these core files through a script? From searching around, I get that the best way is to modify the sudoers file, then run the script with sudo. Is this considered the safest and best way?

Thanks!

Hi Everyone, I have multiple csv files(>100). They are rain-gauge stations files for precipitation measurement. In these files, the numbers of stations are not equal(i.e. there are missing stations). I want only the stations that are present in all the files. The files have unique station id in column #3. I want to ask if this is possible in Linux?

It may be something along: for h in *.cvs; do sed '?????' $h > rippe_$h && mv rippe_$h $h.xls ; done

I have two files which has exact same number of lines.
I want first line of first file should be filename of new file and content of this new file should be first line of second file.
Then second line of first file should be filename of again new file and content of this new file should be second line of second file.
then third line of first file should be filename of again new file and content of this new file should be third line of second file.
and so on...
I am trying to do it using for loop but I am not able to create two for loops.
This is what I have done
Code:

IFS=$'\n'
var=$(sed 's/\"http\(.*\)\/\(.*\).wav\"\,\".*/\2/g' 1797.csv) # filenames of all files
var2=$(sed 's/\"http\(.*\)\/\(.*\).wav\"\,\"\(.*\)\"$/\3/g' 1797.csv) # contents of all files
for j in $var;
do
#Here I do not know how to use $var2
done

Please help.

Hello Folks.

I'm searching for a easy way to rename multiple files from CLI but didn't find any easy way for me so I'm reaching out to you guys for help.

This is what I want to do (from CLII or script). I want to move files with a sequence number on the name of the files (msg0000, msg0001, msg0002 and so on) to let's say msg0066, msg0067 and so on. Each of this file name has two other files (msg0000.wav, msg0000.WAV and msg0000.txt).

The idea is to move them from one directory to another and following a sequence in the file names, is there a way I can do this pain free?

Any help on this matter will be greatly appreciates and I'm talking about over 100 files I need to move following the sequence of the receiving directory.

Thanks!