Redirection. Help Pls.

hey guys,

Let's say I want to find out which log files have related ntp information in them. I use cat and grep to search through the files in /var/log and then export that to a file. this is the command...

# cat /var/log/* | grep ntp > /home/log.txt

The file created from this command will not include the directories the log entries are apart of. Why not? For example, if you do this same command without exporting to the /home/log.txt file it will show you in stdout which directory each log entry is in. Hope I'm making sense here. My question is, is there a clever way to export to a file in a way so that the file created is structured exactly like the stdout of the command below?

# cat /var/log/* | grep ntp

Hey guys,

Something is puzzling me!

I saw someone use the grep in the following way and I'm not sure I understand what it does, and if there's any benefit to using it this way.

Code:

grep X.X.X.X /var/log/log.log | grep -v query

I checked the man file which confirmed that -v is relating to matching non grouping lines (which I'm not sure I fully understand either!) but I don't see any difference in the output of the above command versus the same command without the | grep -v query bit..

Why would you pipe grep into grep unless you were searching for something specific within the search results?

Does query mean something else?

Hi all,

I'm trying to identify files that do not have matches for certain strings. FYI, these are files of DNA sequences and I'm trying to find those that are NOT sampled for any species by my group of interest (e.g., genes that are specific to that group of organisms).

I tried this code but it's actually yielding a list of files that DO match for my regexp.
Code:

for FILENAME in *.fas
do
grep -q -L ">PBAH" $FILENAME && grep -q -L ">SKOW" $FILENAME && grep -q -L ">CGRA" $FILENAME && echo $FILENAME
done

Basically I want to somehow go through and file files that do not contain ">PBAH" ">SKOW" or ">CGRA". Any assistance would be greatly appreciated!

Best,
Kevin

I copied the following from my linux console.

grep -lr "SMTP" *.ini
grep: *.ini: No such file or directory

I wanted to search recursively under current location in files with extenstion .ini
Actually there are files that contain "SMTP" under this directory. But I got the above error message.
What is wrong? I am using centos 6.

Thanks,
3rock

Hi Forum members,

I'm interested to get the date on which particular command was ran.

I've below in my .bashrc

Code:

export HISTTIMEFORMAT="%d/%m/%y %T "

I ran history | grep "cp" | less

I get an output like:

Quote:
1288 27/05/15 09:12:55 sacct -j 767151 --format=elapsed,ncpus,state
27/05 is today's date. But I'm interested for the date, the above output was ran.

What am I missing?

I want to And search grep shell

but It's hard to grep variable


---------------------------------------------------------------
#!/bin/bash


if [ $# -eq 0 ]
then
echo "Ussage: phone searchfor [...searchfor]"
echo "(You didn't tell me what you want to search for )"

else

pass=0
find=""

for idx in $*
do
if [ -n "$idx" ]
then
if [ $pass -eq 0 ]
then
find=$(egrep "$idx" mydata)
pass=1

else

find=$("$find" | grep "$idx")

echo $find
fi
fi

done

if [ -z "$find" ]
then
echo "There is no such thing"
else

echo $find | awk -f display.awk

fi

fi

-----------------------------------------------------

there is one error : command not found

in find=$("$find" | grep "$idx")

how can I grep variable and store it into variable?

I've been using this a lot:

find <directory to start search at> -name "<files to search in>" -type f | xargs grep "<string to search for>"

e.g.

find /usr/include -name "*.h" -type f | xargs grep "#define UINT"

now what if I wanted to output the results to a file?

Hi ,

Please explain what the below command means ..


Code:

if grep -c -i Y $INIFILE > /dev/null

I know what is the use of grep, it is used for finding a character or string in a file. But i could not understand the above form of grep command.

I am new to linux so this might be a simple question, but please throw some light on it.


Edited

And also please explain why they are creating a file in null in the below command

Code:

cat /dev/null > $DATA_DIR/$DATAFILE

Hi Linux Guru's

need some a little help regarding on the jboss command that will validate. The command should only echo either "jboss7" or "jboss4"


however in our jboss7 we got also jboss7modules running and it should not be there from the output

[pogi.ako@server2 ~]$ rpm -qa | grep jboss | grep -v config | awk -F'-' '{print $3}'
jboss7
jbossmodules


using with |tail -1 | head -1
[lemuel.luna@server2 ~]$ rpm -qa | grep jboss | grep -v config | awk -F'-' '{print $3}' |tail -1 | head -1
jbossmodules


but from other servers I see it has different approach

[pogi.ako@server1 bin]$ rpm -qa | grep jboss | grep -v config | awk -F'-' '{print $3}'
jbossmodules
jboss7


[pogi.ako@server1 bin]$ rpm -qa | grep jboss | grep -v config | awk -F'-' '{print $3}' |tail -1 | head -1
jboss7


I'm trying to achieve here on on not to include jbossmodules from the output

hello everyone,
I created a script file (info.sh) in linux centos 6.
location of file is '/etc/init.d/info.sh'
content of file is:

#!/bin/sh
#To get the MAC address
ifconfig | grep HWaddr
#To get the HDD serial no.
hdparm -I /dev/sd? | grep 'Serial\ Number'
#To get the HDD size
hdparm -I /dev/sda |grep "device size"

gave the permission by: chmod 777 /etc/init.d/info.sh
but when i run this file by: /etc/init.d/info.sh
it gives an error like...
-bash: /etc/init.d/info: cannot execute binary file

what should i do?? Actually i have to run this file during boot up..

thanks in advance..