Print Single Quotes Within An Echo Appending To The End Of A File.

Centos 6.5

I ran into an interesting problem (on reddit) that I figured I could solve, but I have not been able to. Its simple,.. I added 'exit 0' to /root/.bashrc, and now I am trying to log in via ssh.

Everytime I do, it immediately exits when it runs the .bash_profile, which sources .bashrc, (which is immediate upon 'logging in')

I've tried:

Code:

ssh root@192.168.1.50 -t vim
vim scp://192.168.1.50/.bashrc
vim scp://192.168.1.50/root/.bashrc
ssh root@192.168.1.50 bash --norc
ssh root@192.168.1.50 /bin/bash --norc --noprofile
ssh -T root@192.168.1.50 "mv /root/.bashrc /root/.bashRC"
scp .bashrc root@192.168.1.50:/root/
ssh root@192.168.1.50 /bin/bash --norc --noprofile -vvvvvvvvvv
ssh -vvvvvv root@192.168.1.50 /bin/bash --norc --noprofile
ssh -vvvvvv root@192.168.1.50 /bin/mv /root/.bashrc /root/.bashRC
ssh -t -t root@192.168.1.50 << EOF
mv /root/.bashrc /root/.bashRC
EOF
ssh -t -t root@192.168.1.50 --norc << EOF
echo HELLO > /root/.bashrc
EOF
ssh -tv root@192.168.1.50 rm .bashrc

So,.. I am unable to get back into the system (as root, no other users exist) after adding 'exit 0' to .bashrc

Anyone feel like explaining why all of these failed (aside from saying SSH interactive logins run the .bash_profile/.bashrc files) or, offering a suggestion that works? Seems like if you have the root password, you should be allowed to modify the login process... since... you know... you are root.

Hi,

I am new to UNIX - i wrote this below script based on the requirement. But i am stuck at the concatenation (at the second last step of the code)

The below code is working fine till the concatenation(second last step) - I need to concatenate Hello to the "physId" e.g. - The filename is UM123456789.20150503 - i am extracting M123456789 and i need to append "HELO" to it at the end. But as per the below script - when i am using the concatenation, it is overwriting the M123456789 and the output thus becomes HELO456789. I am trying to get the output as - M123456789HELO - where am i going wrong?

on the terminal i checked - echo $0 and it gave -> /bin/sh. Hence i wrote the below code.

#!bin/sh
absolutePath=/abc/data/abc_unix/stg/decrypt/*.*
filepath=$(echo ${absolutePath%.*})
echo "$filepath"
filenameext=$(echo ${filepath#/abc*decrypt/})
echo "$filenameext"
file=$(echo ${filenameext#.*})
echo "$file"
extract_physId=$(echo ${file:1:9})
physId=$(echo ${extract_physId})
echo "$physId"
key="$physId"HELO
echo "$key"

Hi guys,

i'm beginner with Unix, I tried my best, but I Really don't know how to finish it .

here's my problem : I have to do something like Student system - student's name | subjects | mark |credits.

after starting script it will ask you for Student's name, then which subject, then the mark will appear.

It's a homework, and I have my own idea how to solve it, but cannot finish it, i don't want complete solution, just a help!

Code:

#!/bin/bash
echo "Students name"
echo -n "Enter student's name: "
read name
echo
case $name in
Example1|Math) echo "C" ;;
Example2|Programming) echo "D" ;;
Example3|WWW) echo "A" ;;
Example4|Economie) echo "-" ;;
esac

I don't now how to bring together case with second things which is "enter subject".

I appreciate any help

Hi All..

I need to give four lines of gap(Freespace) between two command outputs.

what i did was below

Code:

echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
print "***************** LEVEL 2: Truncating  Tables: Success:  tables Truncated ***********************" >> $LOG/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
# Run the load scripts.
echo "***************** LEVEL 3: Loading Dupe Check Tables: Success: Dupe Check tables Loaded***********************" >> $LOG/$LOG_NAME

Is there any better way of writing this command to leave multiple lines between two commands.

Please advise...

I made the mistake of adding an xterm invocation to my ".bashrc" file. My intent was to simply execute an xterm upon initial login to the KDE environment on Debian Wheezy (though the distro probably would have made no difference). What happened is that with each invocation of "xterm", the new xterm would again invoke an "xterm" via the ".bashrc" file. Duh, infinite recursion of xterms upon login. Is there a simple way to invoke an xterm at login that doesn't itself lookup the ".bashrc" file? By the time someone answers this, I will probably find and answer somewhere in the bash/xterm man pages, but thought I'd throw it out there. Really felt stupid after having realized my mistake. Had to login to recovery command line mode and replace the ".bashrc" file with "/etc/skel/.bashrc". Cheerio

Hi,

i have a small problem on my system... I recently wrote a small bash script and added it via crontab -u root -e and it's executed as it should.
Then a few days after i did edit my bash script, but once it is run by cron it doesn't reflect the changes i made to the script. I did manually restart crond, tryed sync, moved my script, renamed it even rstart the server - no success.
If i run my script manually it returns me the expected output.
part of my script (/root/sd.sh):
Code:

#!/bin/sh

echo -n "Checking Raid... "
RAID=`tw-cli /c0/u0 show status | cut -c17-31 | grep -ci OK`
RAIDSTATUS=`tw-cli /c0/u0 show status | head -n1 | cut -c17-31`
if [ $RAID -eq 0 ]; then
  VERIFYING=`tw-cli /c0/u0 show status | cut -c17-31 | grep -ci VERIFYING`
  REBUILDING=`tw-cli /c0/u0 show status | cut -c17-31 | grep -ci REBUILDING`
  if [ $VERIFYING -eq 1 ]; then
    CURRENTSTATUS=`tw-cli /c0/u0 show verifystatus | head -n1 | cut -c46-49`
  fi
  if [ $REBUILDING -eq 1 ]; then
    CURRENTSTATUS=`tw-cli /c0/u0 show rebuildstatus | head -n1 | cut -c47-50`
  fi
  echo "Raid is busy (Raid $RAIDSTATUS$CURRENTSTATUS)"
  exit 1
fi
echo "Raid is idle (Raid $RAIDSTATUS)"

echo -n "Checking for logged in Users... "
USERS=`who | wc -l`
if [ $USERS -gt 0 ]; then
  echo "Users online"
  exit 1
fi
echo "None logged in"

crontab -l :
Code:

root@monster:~# crontab -l
# Edit this file to introduce tasks to be run by cron.
#
# Each task to run has to be defined through a single line
# indicating with different fields when the task will be run
# and what command to run for the task
#
# To define the time you can provide concrete values for
# minute (m), hour (h), day of month (dom), month (mon),
# and day of week (dow) or use '*' in these fields (for 'any').#
# Notice that tasks will be started based on the cron's system
# daemon's notion of time and timezones.
#
# Output of the crontab jobs (including errors) is sent through
# email to the user the crontab file belongs to (unless redirected).
#
# For example, you can run a backup of all your user accounts
# at 5 a.m every week with:
# 0 5 * * 1 tar -zcf /var/backups/home.tgz /home/
#
# For more information see the manual pages of crontab(5) and cron(8)
#
# m h  dom mon dow   command
*/10 * * * * /root/sd.sh | logger
*/30 * * * * /root/dropbox.sh > /dev/null

syslog:
Code:

Mar 21 09:10:01 monster /USR/SBIN/CRON[3998]: (root) CMD (/root/sd.sh | logger)
Mar 21 09:10:01 monster logger: Checking Raid... Raid is busy (Raid )
Mar 21 09:17:01 monster /USR/SBIN/CRON[4045]: (root) CMD (   cd / && run-parts --report /etc/cron.hourly)
Mar 21 09:20:01 monster /USR/SBIN/CRON[4105]: (root) CMD (/root/sd.sh | logger)
Mar 21 09:20:01 monster logger: Checking Raid... Raid is busy (Raid )
Mar 21 09:30:01 monster /USR/SBIN/CRON[4266]: (root) CMD (/root/sd.sh | logger)
Mar 21 09:30:01 monster /USR/SBIN/CRON[4265]: (root) CMD (/root/dropbox.sh > /dev/null)
Mar 21 09:30:01 monster logger: Checking Raid... Raid is busy (Raid )

when i run sh /root/sd.sh
Code:

root@monster:~# sh /root/sd.sh
Checking Raid... Raid is idle (Raid OK)
Checking for logged in Users... Users online
root@monster:~#

Any ideas why? - any help or thoughts appreciated

regards
Pat

i need to complete this exercise but my code has some issues
HERE is the PRoblem:
Create a script that can accept ANY amount of numbers from the command line. Process the numbers one at a time, where numbers greater than 10 print “large”, numbers less than or equal to 10 print “small”
E.g. process 5 10 15 would print
small
small
large

and here is my code so far
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi

any help would be greatly appreciated

Hi all,

Been reading on stdin, stdout and stderr and encounter 2 questions, hope gurus here can advise.

0 = stdin
1 = stdout
2 = stderr

Code:

Sun Dec 21 03:53:42 SGT 2014 > cat test5.sh
#!/bin/bash

echo "Please enter value for name :"
read name
echo "Your name is $name."

echo "Next echo will be a syntax error"
ehco

Code:

Sun Dec 21 03:53:46 SGT 2014 > test5.sh 1> output.txt 2> error.txt
Noob

Sun Dec 21 03:54:56 SGT 2014 > cat output.txt
Please enter value for name :
Your name is Noob.
Next echo will be a syntax error

Sun Dec 21 03:55:23 SGT 2014 > cat error.txt
/home/alan/scripts/test5.sh: line 8: ehco: command not found
Sun Dec 21 03:55:26 SGT 2014 >

Which so far all is good and the correct way to output everything including error to a single file is

Code:

Sun Dec 21 03:59:14 SGT 2014 > test5.sh > output.txt 2>&1

Q1) How is a command being interpreted in linux , the sequence in which it is interpreted ? from left to right ? right to left ?

Shouldn't it be

Code:

test5.sh 2>&1 1>output.txt 
or 
test5.sh 2>&1>output.txt ?

Regards,
Noob

Code:

PREFIX=192.168.1
OCTET=1
while [ $OCTET -lt "255" ]; do
    echo -en "Pinging ${PREFIX}.${OCTET}..."
    ping -c1 -w1 ${PREFIX}.${OCTET} > /dev/null 2>&1
    if [ "$?" -eq "0" ]; then
       echo "OK"
    else
       echo "Failed"
    fi
    let OCTET=$OCTET+1
done

My question is, in the penultimate line, why is it OCTET, and not $OCTET, with a dollar before it, meaning, the variable?

What if it were written:
Code:

let $OCTET=$OCTET+1

Like in C++ (I think) or Python or whatever?

hi all

I am learning systemd and how to add new services as part of the LFS201 course and I have a question about the services:
Code:

Lab 4.2: Adding a New Startup Service with systemd
For example a very minimal file named
/etc/systemd/system/fake2.service:
[Unit]
Description=fake2
After=network.target
[Service]
ExecStart=/bin/echo I am starting the fake2 service
ExecStop=/bin/echo I am stopping the fake2 service
[Install]
WantedBy=multi-user.target

Code:

root@ubuntu:/etc/systemd/system# systemctl start fake.service
root@ubuntu:/etc/systemd/system# systemctl status fake.service
 fake.service - fake
   Loaded: loaded (/etc/systemd/system/fake.service; disabled; vendor preset: enabled)
   Active: inactive (dead)

May 16 11:41:05 ubuntu systemd[1]: Started fake.
May 16 11:41:05 ubuntu systemd[1]: Starting fake...
May 16 11:41:05 ubuntu echo[1798]: I am starting the fake2 service
May 16 11:41:05 ubuntu echo[1800]: I am stopping the fake2 service
root@ubuntu:/etc/systemd/system# ps aux | grep fake*
root      1809  0.0  0.0  13688  2272 pts/8    S+   11:41   0:00 grep --color=auto fake.service
root@ubuntu:/etc/systemd/system#

as you can see the fake2 service is really only two lines. And when I grep for the service via ps I can't fine it. I guess it is because it has finished running. I am wondering how can I change it so that I can keep it running?

thanks