Delay Calculation From Trace Files Of AODV / LAR Protocols

when i am running delay.awk file on AODV.tr and LAR.tr For AODV.tr , it is giving me the o/p value as some delay
but for LAR , its showing me the follwing error

gawk: e2edelay.awk:93: (FILENAME=larscen5.tr FNR=36516130) fatal: division by zero attempted

I was unable to recify the error. could you please help me.
thank you so much

this is the code of awk file which i am using for calculation of delay. kindly help

# http://205.196.121.184/fnufnnc17mwg/...c/e2edelay.awk
# http://mohittahiliani.blogspot.dk/20...s-for-ns2.html
# ===================================================================

# AWK Script for calculating:

# => Average End-to-End Delay.

# ===================================================================



BEGIN {

seqno = -1;

# droppedPackets = 0;

# receivedPackets = 0;

count = 0;

}

{

if($4 == "AGT" && $1 == "s" && seqno < $6) {

seqno = $6;

}
# else if(($4 == "AGT") && ($1 == "r")) {

# receivedPackets++;

# } else if ($1 == "D" && $7 == "tcp" && $8 > 512){

# droppedPackets++;

# }

#end-to-end delay

if($4 == "AGT" && $1 == "s") {

start_time[$6] = $2;

} else if(($7 == "cbr") && ($1 == "r")) {

end_time[$6] = $2;

} else if($1 == "D" && $7 == "cbr") {

end_time[$6] = -1;

}

}


END {

for(i=0; i<=seqno; i++) {

if(end_time[i] > 0) {

delay[i] = end_time[i] - start_time[i];

count++;

}

else

{

delay[i] = -1;

}

}

for(i=0; i<count; i++) {

if(delay[i] > 0) {

n_to_n_delay = n_to_n_delay + delay[i];

}

}

n_to_n_delay = n_to_n_delay/count;



print "\n";

# print "GeneratedPackets = " seqno+1;

# print "ReceivedPackets = " receivedPackets;

# print "Packet Delivery Ratio = " receivedPackets/(seqno+1)*100
#"%";

# print "Total Dropped Packets = " droppedPackets;

print "Average End-to-End Delay = " n_to_n_delay * 1000 " ms";

print "\n";

}


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