Hi,
I am working with a software that is based on Perl scripting and I have encountered with a bash scripting error. So as I am not familiar with bash scripting well, I don't know how I can solve.
sh: -c: line 1: syntax error near unexpected token `('
sh: -c: line 1: ` 32(andRlooks_unw'
It should be mentioned that my $SHELL is /bin/bash. Could you please guide me what '-c' is? where is it? if I change the shebang (the #!/bin/sh part) to #!/bin/bash, the problem will be solved?
Regards,
Zahra
Hi!
I wrote a script shell about changing IP of the httpd.conf from text file and saving a new httpd.conf file for all IPs in the text file. The code is below, Im using mremote on windows (RHEL Release 5.7), and getting this error:
./script1.sh: line 19: syntax error: unexpected end of file
Please help me about that error. Thanks!
(ps: line 19 is the last line in the code => done < "$filename" )
#!/bin/bash
DATE='date +%Y%m%d_%H:%M:%S'
NAME=httpd_ip_change
EXTENSION=conf
max=10
filename="$1"
while read -r line
for ((i=2; i<=$max; ++i ))
do
touch $NAME$i.$EXTENSION.$DATE
sed "s/<VirtualHost 10.11.92.81:80>/$line/g" ./httpd.conf > $NAME$i.$EXTENSION.$DATE
done < "$filename"
I have reasonable experience in linux based systems. I want to learn a scripting language , can anyone out there suggest which one is the best to start with ? I would be grateful if anyone can provide me with links / books references as well ...
I'm trying to loop through a query in SQLDeveloper by passing the query a different Period and I'm having a problem getting the syntax correct.
Individually the following works correctly on its own:
Code:
#!/bin/bash
for i in `seq -f "%02g" 1 5`;
do
echo $i
done
$ ./test.sh
1
2
3
4
5
the following also executes correctly:
Quote:
sqlplus table1/$userpass@Mytable <<EOF
@./sqlcode.sql $i
EOF
but when I try to wrap the loop around my sqlplus command
Code:
#! /bin/sh
userpass=read
for i in `seq -f "%01g" 1 3`;
do
sqlplus -S table1/$userpass@Mytable <<EOF
@./sqlcode.sql $i
EOF
done
I get the following error:
./test.sh: line 13: syntax error: unexpected end of file
Does anyone have any ideas on what's going on?
Hi,
i am using ubuntu 12.04 i working on scripting i want know how to change set of user passwords in shell scripting .
Ok yes this is a homework assignment BUT I am NOT looking to have the answers given to me. I am in the 6th week of my first Linux class ever and we are in our few weeks of beginning scripting. I have some ideas of what to do or where to start but not many and no one to bounce any ideas off...we are using UNIX Bash shell so any others I have no clue. The scenario is that I need a script that searches all my users home directories for bad words. I need the script to report to the screen certain info like username and word found and path. It should ask a user if it is good or bad and if bad be put into a file of list of bad file names, if good remove from list and no longer flagged by the script. What I have so far is wanting to somehow do a loop. I do know that if I do a grep -r -e kill -e steal /home/* I get a list of what I need. I also know that the list is separated by delimiters which I can pipe to get a variable for the things I need. I also know that I can put it to a file with a > filename.txt
What I have no clue is how to start a loop that would do this...
for each line in filename.txt
UNAME=...
LOC=...
TXT=...
echo "Username: $UNAME, Line with bad word found: $TXT, and Path and file name: $LOC. Is this a BAD file? (Y)"
Read YORN
if ["$YORN" = "Y" ]; then
>> (line of text from grep) badfiles.txt
fi
Next or whatever goes there...sorry if this is crazy I just really need some direction. I am trying to learn so please don't give me the answer...that will do nothing for me and I will not be able to explain the code I came up with.
hi,
I am newbie in Linux shell scripting.Can anybody help me to check the presence of file identified by variable in Shell scripting?
For example: I am reading the content of a file using while command as below:
"while read -r line
do
code block
done < file_name"
Now in this case every line in file gets stored in the variable 'line' one by one.Problem here is every line in the file is nothing but the file_path of another file say xyz.txt and I am checking presence of this xyz.txt file using below command:
if [-f $line]
as 'line' is the variable which stores file path of xyz.txt but it is not working. It is unable to check the presence of this xyz.txt file as i am addressing it with the variable 'line'.
Please help me.Thanks in advance.
I am looking to display the w (who) command to show only the
User TTY IDLE
http://screencast.com/t/vXb74kguJ
13:15:38 up 8 days, 16:48, 47 users, load average: 1.47, 0.95, 0.51
USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT
rf3 pts/0 192.168.11.72 05:58 48.00s 6.60s 0.00s -bash
user21 pts/1 192.168.21.177 04:32 8:41m 0.05s 0.00s -bash
user7 pts/2 192.168.11.114 17Mar15 6days 1.07s 0.00s -bash
user7 pts/3 192.168.11.114 20Mar15 4:54m 9.75s 0.00s -bash
user6 pts/4 192.168.11.85 11:02 7.00s 55.58s 0.01s -bash
user14 pts/5 192.168.11.183 05:06 29:08 2.80s 0.01s -bash
user14 pts/6 192.168.11.155 05:30 13:28 2.75s 0.00s -bash
user23 pts/7 192.168.11.62 05:48 25:09 0.95s 0.00s -bash
rf5 pts/8 192.168.11.118 05:58 6:51 5.30s 0.01s -bash
user2 pts/9 192.168.11.140 08:34 1:19 44.74s 0.00s -bash
user14 pts/10 192.168.11.141 06:02 12:14 9.46s 0.00s -bash
rf12 pts/12 192.168.11.69 06:02 2:07 9.44s 0.00s -bash
root pts/13 localhost.locald 12:29 9:10 0.05s 0.05s -bash
rf6 pts/14 192.168.11.79 06:04 14.00s 9.05s 0.00s -bash
user14 pts/15 192.168.21.113 06:23 11:29 1.71s 0.00s -bash
user5 pts/16 192.168.11.126 06:24 6:56 4.59s 0.00s -bash
user5 pts/17 192.168.11.126 06:25 6:19 31.59s 0.01s -bash
user11 pts/18 192.168.11.125 06:26 28:10 2.90s 0.01s -bash
user12 pts/19 192.168.21.123 06:35 13:16 0.88s 0.00s -bash
rf7 pts/20 192.168.11.80 06:35 2:06 7.64s 0.00s -bash
user12 pts/21 192.168.21.123 06:36 41:55 0.12s 0.00s -bash
So far I have this
w | awk {'printf ("6s\ts\n", $1, $2, $3, $5)'} |more
13:20:16 up
USER TTY
rf3 pts/0
user21 pts/1
user7 pts/2
user7 pts/3
user6 pts/4
user14 pts/5
user14 pts/6
user23 pts/7
rf5 pts/8
user2 pts/9
user14 pts/10
rf12 pts/12
root pts/13
This only shows the 2 columns
w |awk '{print $1, $2, $3, $5}'
13:21:01 up 8 16:53,
USER TTY FROM IDLE
rf3 pts/0 192.168.11.72 20.00s
user21 pts/1 192.168.21.177 8:46m
user7 pts/2 192.168.11.114 6days
user7 pts/3 192.168.11.114 4:59m
user6 pts/4 192.168.11.85 3:42
user14 pts/5 192.168.11.183 34:31
user14 pts/6 192.168.11.155 18:51
user23 pts/7 192.168.11.62 30:32
rf5 pts/8 192.168.11.118 12:14
user2 pts/9 192.168.11.140 1.00s
user14 pts/10 192.168.11.141 17:37
rf12 pts/12 192.168.11.69 30.00s
This shows some what hard to read and the columns don't line up correctly
is there a way to tab them in to columns that line up properly, or even something similar to the TOP command where the list will keep refreshing?
I need to compare a value with different fixed value. Below is the code concept I implemented in my bash script but its giving me error.
Here "a' is the nameserver value that I extract using command line from /etc/resolv.conf. I did not put command here.
#! /bin/bash
a=1.2.3.4
if [ $a == 1.2.3.4 || 5.6.7.8 || 8.9.1.4]
then
echo " You have correct ntpserver"
else
echo"wrong ntpserver"
fi
Am I comparing the value correctly or any suggestion?
Thank you
Hello,
I am getting the follwoing error for Red Hat Enterprise Linux Server release 6.6
sudo su -
sudo: >>> /etc/sudoers: syntax error near line 118 <<<
sudo: parse error in /etc/sudoers near line 118
sudo: no valid sudoers sources found, quitting
sudo: unable to initialize policy plugin
cd /etc/sudoers.d/
-bash: cd: /etc/sudoers.d/: Permission denied
Could you help me to figure it out. As a root user am able to access but as normal user it is not allowing to sudo su - command.
vi /etc/sudoers.d/access
username ALL=(ALL) NOPASSWD: ALL
Please let me know if any additional formation required.
This is my script and the syntax to run this script is give ip and next will be the file or script you want to perform on remote server
#!/bin/bash
# The private key used to identify this machine
IDENTITY_KEY=/home/adnew.pem
syntax()
{
echo "Syntax: Ec2.sh server_ip scriptFile]"
echo "For example: ./Ec2.sh server_ip scriptFile"
exit 1
}
if [ $# -ne 2 ]
then
echo not enough arguments
syntax
fi
echo "Running script $2 on $1"
ssh -ttq -i $IDENTITY_KEY ec2-user@$1 sudo -i 'bash -s' < $2
exit
exit
echo "Done"
on script file i have give for testing
touch /root/test
ls /root/test
exit
exit
it makes the file but do not show the ls output by giving error
tcgetattr: Inappropriate ioctl for device
exit
what I have to do ??