Remove Column From .CSV Using AWK Command

Hi,

I am not able to replace the $@@$ with ,. below is the content in which i want $@@$ should be replace with ,

"Harbola$@@$ Gopal (ssoid)","agaga"
"Gaurav$@@$ Gaurav (ssoid)","abc"

so that the result can come like this.

"Harbola, Gopal (ssoid)","agaga"
"Gaurav, Gaurav (ssoid)","abc"

Can anyone help me in this

Hi All,

Using grep command with a defined string, you will get the row. Can I get the column instead of row? For example,

the file content is as below:

AA BB
123 456
789 ABE

execute 'grep ABE file' will give you "789 ABE". Is there any way to get the column:
BB
456
ABE
?

Thank you very much.

I have connected to mysql console by "mysql -uroot -p" , then use the command "show processlist ;" to list the processes , but I can't see the result , may be the command is too long , the column only allow around 85 characters , the command should over the limit , how can I see the full command ?

thanks

Apologies. I've been out of Unix for 14 years, and the gears have rusted. Also, Unix has changed - enough similarities to memory that I'm pretty comfy though.

Glad to see lots of info available via google. However changes are going to take getting used to. Have set up a testbed of 3 nearly identical machines, hoping to make an (at home) private network where I can automate installs and set-ups using NIS and NFS (Similar to work I once did).

Have found useful scripts interspersed with comments, would like to copy and paste them to a bash script that:

Reads the line.
Echos the line.
Reads the reply.
Executes what is typed.

Essentially, by making myself type (or copy & paste) the commands I think I'll become familiar.

Figured I'd use a spreadsheet, select the file, and paste into column B of the spreadsheet. In column A I'd paste:

echo "

and in column C I'd paste:

"

Then I'd cut and paste into a text document, insert the lines:

read A
$A

behind every command necessary to the actual task.

Figured I'd have to escape the ' and ".

Ran a test (test.bash):

#!/bin/bash
for i in `seq 1 10`;
do
echo "Enter a command:"
read A
echo "Trying $A"
$A
done

works fine when I type

ls -alg

but not so when I type

ls -alg | grep dwrx

so I'm wondering if someone has a suggestion?

Thanks for any ideas.

Hi

RHEL 6.4 (64 Bit) is running as a Virutal Machine in a VCenter Server 5.5
As per our request, Vmware team added 500GB of disk space to this VM. Disk is not visible in "fdisk -l" after run the following command/script, but the new disk could be seen from the "multipath -l" command.

for i in `ls -ld /sys/class/scsi_host/host* | awk '{print $9}' `
do
echo "- - -" > $i/scan
done

Could someone clarify why it is not visible in "fdisk -l" output?

I have several of csv files, I want to remove the first row (header) and first column as well. This is my code, but it overwrites the original files with no content inside:

for x in *.csv;
do
sed '1d' $x | cut -d, -f 1 > "$x";

done

Help would be highly appreciated.

Note: Ubuntu 14 latest release

I am a highly experienced unix user with many years of experience. However, I retired 13 years ago so I can't remember some simple things so forgive me for posting here.

I am trying to use the "zenity --list --radiolist" command. Now this requires that the list of items be last and be of the form FALSE <item name> as in FALSE "Choice 1" FALSE "Choice 2" That's easy without variables. It would be zenity --list --radiolist [other options here] FALSE "Choice 1" FALSE "Choice 2 Works fine.

But what I have is a list of choices in an array. Each of these is a string of multiple words and I have tried (nearly?) everything using echo command piped into zenity (supposed to work) to including an array element in the line with all sorts of quotes, single quotes, escaping quotes, etc. I have even included the "FALSE" in the variable so as not to have to generate it. Nothing works. When using the set -x, it shows that the shell has put a single quote around each word which makes each word a separate parameter.

I have searched all sorts of examples of zenity but the requirement for the word "FALSE" between each item while using variables is never shown.

If anyone has a working example of something like this (or any simple alternative:
JTemp[3]="This is a string"
echo "FALSE "${Jtemp[3]} | zenity --list --radiolist --text "Select Topic" --column "Topic" --column "Pick one" which should display a radiobox with one entry, I would appreciate it. I could then expand it to include all the array elements.

I know I am doing something simple wrong. I just can't figure it out.

Note that I am writing this on a windows machine and using a non-internet-connected linux machine for my work so if I typed the command line wrong, it may be a problem here and not on the real machine.

Thanks for any help.

Hello,

I am trying to install OCI8. I'm pretty sure the last thing I need to do is run the "./configure" command, but no matter where I try to run it, it gives me back a "file not found" or "command not found" error. I have tried this on CentOS and Fedora and always install PHP with yum. I have done many GUI searches looking through the file system for "php" and have tried to run ./configure in every php folder I can find but the command never runs. Any suggestions are very much appreciated. Thanks so much!

-Matt

P.S. Do I even need to do this if I already edited the "php.ini" file and installed OCI8 with PECL? Thanks!

i need to complete this exercise but my code has some issues
HERE is the PRoblem:
Create a script that can accept ANY amount of numbers from the command line. Process the numbers one at a time, where numbers greater than 10 print “large”, numbers less than or equal to 10 print “small”
E.g. process 5 10 15 would print
small
small
large

and here is my code so far
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi

any help would be greatly appreciated

when i am running delay.awk file on AODV.tr and LAR.tr For AODV.tr , it is giving me the o/p value as some delay
but for LAR , its showing me the follwing error

gawk: e2edelay.awk:93: (FILENAME=larscen5.tr FNR=36516130) fatal: division by zero attempted

I was unable to recify the error. could you please help me.
thank you so much

this is the code of awk file which i am using for calculation of delay. kindly help

# http://205.196.121.184/fnufnnc17mwg/...c/e2edelay.awk
# http://mohittahiliani.blogspot.dk/20...s-for-ns2.html
# ===================================================================

# AWK Script for calculating:

# => Average End-to-End Delay.

# ===================================================================



BEGIN {

seqno = -1;

# droppedPackets = 0;

# receivedPackets = 0;

count = 0;

}

{

if($4 == "AGT" && $1 == "s" && seqno < $6) {

seqno = $6;

}
# else if(($4 == "AGT") && ($1 == "r")) {

# receivedPackets++;

# } else if ($1 == "D" && $7 == "tcp" && $8 > 512){

# droppedPackets++;

# }

#end-to-end delay

if($4 == "AGT" && $1 == "s") {

start_time[$6] = $2;

} else if(($7 == "cbr") && ($1 == "r")) {

end_time[$6] = $2;

} else if($1 == "D" && $7 == "cbr") {

end_time[$6] = -1;

}

}


END {

for(i=0; i<=seqno; i++) {

if(end_time[i] > 0) {

delay[i] = end_time[i] - start_time[i];

count++;

}

else

{

delay[i] = -1;

}

}

for(i=0; i<count; i++) {

if(delay[i] > 0) {

n_to_n_delay = n_to_n_delay + delay[i];

}

}

n_to_n_delay = n_to_n_delay/count;



print "\n";

# print "GeneratedPackets = " seqno+1;

# print "ReceivedPackets = " receivedPackets;

# print "Packet Delivery Ratio = " receivedPackets/(seqno+1)*100
#"%";

# print "Total Dropped Packets = " droppedPackets;

print "Average End-to-End Delay = " n_to_n_delay * 1000 " ms";

print "\n";

}