Check Empty Variable Without Comments

Hello,

They gave me this:
Code:

#!/bin/bash

# Write error message on stderr and die
function die() {
  echo "$@" >&2
  exit 1
}

# Load var from properties files
function load() {
  for propertie in "$@" ; do
    [[ -f "${propertie}" ]] || die "load() : \"${propertie}\" don't exist !"
    while read ; do
echo "${REPLY%=*}"
echo "${REPLY#*=}"
      [[ -n "${REPLY%%=*}" && -z "${REPLY#*=}" ]] || die "load() : Variable \"${REPLY%%=*}\" is empty!"
      eval "${REPLY%%=*}"=\'"${REPLY#*=}"\'
    done < "${propertie}"
  done
}

load "manage_srcds.conf"
echo "SRCDS_TICKRATE=$SRCDS_TICKRATE"
echo "SRCDS_SCREEN=$SRCDS_SCREEN"
echo "SRCDS_SRCDS_GAME_NAME=$SRCDS_GAME_NAME"
echo "SRCDS_MAXPLAYERS=$SRCDS_MAXPLAYERS"

but, return:
Quote:
###################################################
###################################################
load() : Variable "###################################################" is empty!

cat manage_srcds.conf

I just wish that there was no empty variable excluding those who do not have integer.

Best regards,

Parameter $1 Isn't Returned After A Case (bash Scripting)

Hello everyone,

I recently started using "function" and "case" in linux but I came across a slight problem

My code:

Code:

function Return
{
echo $1
}

case "$1" in 
 ""       ) echo "give parameters please";;
 [0-9]*   ) echo "No numbers please";;
 *        ) Return;;

So whenever the first parameter is a simple word I would like it returned, but it seems like there is no returned string (empty space)

Also I know I can just write "echo $1" instead of Return, but I'd like to use a function for this.

Can anyone tell me why the function doesn't return $1? Thanks!

How Can I Grep Variable?

I want to And search grep shell

but It's hard to grep variable

---------------------------------------------------------------
#!/bin/bash

if [ $# -eq 0 ]
then
echo "Ussage: phone searchfor [...searchfor]"
echo "(You didn't tell me what you want to search for )"

else

pass=0
find=""

for idx in $*
do
if [ -n "$idx" ]
then
if [ $pass -eq 0 ]
then
find=$(egrep "$idx" mydata)
pass=1

else

find=$("$find" | grep "$idx")

echo $find
fi
fi

done

if [ -z "$find" ]
then
echo "There is no such thing"
else

echo $find | awk -f display.awk

fi

fi

-----------------------------------------------------

there is one error : command not found

in find=$("$find" | grep "$idx")

how can I grep variable and store it into variable?

Mutt Does Not Show Full Subject

I use following shell script to send email. But the subject of email always shows "This" instead of "This is L_1.R is finished". You may refer http://www.linuxquestions.org/questions/linux-newbie-8/how-to-define-variable-in-%60ssh%60-4175540566/
Code:

host_list=("c15-0330-01.ad.mtu.edu" "c15-0330-02.ad.mtu.edu" "c15-0330-03.ad.mtu.edu" "c15-0330-04.ad.mtu.edu")
program=("L_1" "L_2" "L_3" "L_4")
subject="The job is finished"
ssh -f c15-0330-01.ad.mtu.edu 'echo' "the job ${program[0]} is finished" '|' 'mutt "zwang10@mtu.edu" -s' "This is "${program[0]}".R is finished";

Help With 'CASE'

Hi guys,

i'm beginner with Unix, I tried my best, but I Really don't know how to finish it .

here's my problem : I have to do something like Student system - student's name | subjects | mark |credits.

after starting script it will ask you for Student's name, then which subject, then the mark will appear.

It's a homework, and I have my own idea how to solve it, but cannot finish it, i don't want complete solution, just a help!

Code:

#!/bin/bash
echo "Students name"
echo -n "Enter student's name: "
read name
echo
case $name in
Example1|Math) echo "C" ;;
Example2|Programming) echo "D" ;;
Example3|WWW) echo "A" ;;
Example4|Economie) echo "-" ;;
esac

I don't now how to bring together case with second things which is "enter subject".

I appreciate any help

Better Way Of Writing This Command Of Leaving Multiple Blank Lines

Hi All..

I need to give four lines of gap(Freespace) between two command outputs.

what i did was below

Code:

echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
print "***************** LEVEL 2: Truncating  Tables: Success:  tables Truncated ***********************" >> $LOG/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
# Run the load scripts.
echo "***************** LEVEL 3: Loading Dupe Check Tables: Success: Dupe Check tables Loaded***********************" >> $LOG/$LOG_NAME

Is there any better way of writing this command to leave multiple lines between two commands.

Please advise...

Basic Bash Script

Code:

PREFIX=192.168.1
OCTET=1
while [ $OCTET -lt "255" ]; do
    echo -en "Pinging ${PREFIX}.${OCTET}..."
    ping -c1 -w1 ${PREFIX}.${OCTET} > /dev/null 2>&1
    if [ "$?" -eq "0" ]; then
       echo "OK"
    else
       echo "Failed"
    fi
    let OCTET=$OCTET+1
done

My question is, in the penultimate line, why is it OCTET, and not $OCTET, with a dollar before it, meaning, the variable?

What if it were written:
Code:

let $OCTET=$OCTET+1

Like in C++ (I think) or Python or whatever?

Help With Applying Passing Parameters

i need to complete this exercise but my code has some issues
HERE is the PRoblem:
Create a script that can accept ANY amount of numbers from the command line. Process the numbers one at a time, where numbers greater than 10 print �large�, numbers less than or equal to 10 print �small�
E.g. process 5 10 15 would print
small
small
large

and here is my code so far
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi

any help would be greatly appreciated

Simple Ping Bash Script

Hello, I am trying to implement this script, but for some reason, it limits to pinging 192.1681.1 and then 192.168.1.2 infinitely.
Any idea what is wrong with it? Thanks!

Quote:
PREFIX=192.168.1
OCTET=1
while [ "$OCTET" -lt "255" ]; do
echo -en "Pinging ${PREFIX}.${OCTET}..."
ping -c1 -w1 ${PREFIX}.${OCTET}
if [ "$?" -eq "0" ]; then
echo "OK"
else
echo "Failed"
let OCTET=$OCTET+1
fi
done

"vconsole.conf" Show Unicode

Hi!

Here is mine configuration and I want make it show unicode(russian) in console, it works perfect in X11 but not when I logging into tty.

vconsole.conf
Code:

LOCALE="en_US.UTF-8"
KEYMAP="sv-latin1"
FONT_UNIMAP="lat1"
FONT_MAP="ISO8859-1"
CONSOLEFONT="ruscii_8x8"
HARDWARECLOCK="localtime"
TIMEZONE="Europe/Stockholm"
USECOLOR="yes"

Why Wont My Code Work, " SyntaX Error: Unexpected End Of File"

i have been trying to get this peice of code to work but i cant seem to get it to work.
im just starting out coding and kinda poking around in the dark to get this resolved, any help would be much appriciated, thankyou

Quote:
#!/bin/bash

echo "Would you like to scan using nmap or hping?"

read scanner

if "$scanner" = "nmap" : then

echo "Enter the starting IP address :"

read FirstIP

echo "Enter the last IP address :"

read LastIP

echo "Enter the port number you want to scan for :"

read port

nmap -sT $FirstIP-$LastIP -p $port -oG web
cat web | grep open > web1
cat web1 | cut -f2 -d ":" | cut -f1 -d "(" > web2
cat web2

elit

echo "Which IP address would you like to scan?"

read IPaddress

echo echo "What port would you like to scan for ?"

read hpingport

echo "How many packets would you like to send?"

read packets

hping3 -c $packets $IPaddress -p $hpingport > hpingscan

cat hpingscan
thankyou for any help

Check Empty Variable Without Comments

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