What Ftp Server Is Running

I have installed vsftp to the server , the status is running now , but when use the command "ftp localhost" , it pops the "421 Service not available." , would advise what is wrong ? thanks

bash-3.2# /etc/rc.d/init.d/vsftpd status
vsftpd (pid 580) is running...
bash-3.2# ps -ef |grep vsftpd
root 580 1 0 15:44 ? 00:00:00 /usr/sbin/vsftpd /etc/vsftpd/vsftpd.conf
root 607 467 0 15:45 pts/0 00:00:00 grep vsftpd
bash-3.2# ftp localhost
Connected to localhost (127.0.0.1).
421 Service not available.

Hi,

I am running awk command on remote server it is not giving desired results but if i run the same command on local server. it works as expected. Can anybody help me to resolve this and let me know the logic behind this?

Remote server

# ssh test 'free -g | grep Mem | awk -F " " '{ print $2 }''
awk: cmd. line:1: {
awk: cmd. line:1: ^ unexpected newline or end of string

local server
# free -g | grep Mem | awk -F " " '{ print $2 }'
31


Thanks in advance.

I am using the following two commands to output CPU and RAM usage on a Linux machine.

Code:

/bin/grep 'cpu ' /proc/stat | awk '{usage=($2+$4)*100/($2+$4+$5)} END {print usage "%"}'

/usr/bin/free | grep Mem | awk '{print $3/$2 * 100.0 "%"}'

My problem is that the output is like this

Quote:
5.33672%
13.9723%
Is there a way to output a single number? For example

Quote:
5
13
Thank you

I am have a bash script like this:

#!/bin/bash
while true;
do
(printf %s "$(date '+%A %W %Y %X')"; echo -n ", " ; printf %s "$(ps -eo pcpu,pmem,comm | grep statsd)") >> tope.txt;
sleep 2;
done

What I want is the output of this command be entered into tope.txt like this:

Friday 20 2015 11:28:21, 0.0 0.4 /usr/libexec/systemstatsd

but what I get is output like this in multiline. :

Friday 20 2015 11:28:21
,
0.0 0.4 /usr/libexec/systemstatsd

What can I do to fix this?

Hey guys,

Something is puzzling me!

I saw someone use the grep in the following way and I'm not sure I understand what it does, and if there's any benefit to using it this way.

Code:

grep X.X.X.X /var/log/log.log | grep -v query

I checked the man file which confirmed that -v is relating to matching non grouping lines (which I'm not sure I fully understand either!) but I don't see any difference in the output of the above command versus the same command without the | grep -v query bit..

Why would you pipe grep into grep unless you were searching for something specific within the search results?

Does query mean something else?

Hi Linux Guru's

need some a little help regarding on the jboss command that will validate. The command should only echo either "jboss7" or "jboss4"


however in our jboss7 we got also jboss7modules running and it should not be there from the output

[pogi.ako@server2 ~]$ rpm -qa | grep jboss | grep -v config | awk -F'-' '{print $3}'
jboss7
jbossmodules


using with |tail -1 | head -1
[lemuel.luna@server2 ~]$ rpm -qa | grep jboss | grep -v config | awk -F'-' '{print $3}' |tail -1 | head -1
jbossmodules


but from other servers I see it has different approach

[pogi.ako@server1 bin]$ rpm -qa | grep jboss | grep -v config | awk -F'-' '{print $3}'
jbossmodules
jboss7


[pogi.ako@server1 bin]$ rpm -qa | grep jboss | grep -v config | awk -F'-' '{print $3}' |tail -1 | head -1
jboss7


I'm trying to achieve here on on not to include jbossmodules from the output

Hi all,

I'm trying to identify files that do not have matches for certain strings. FYI, these are files of DNA sequences and I'm trying to find those that are NOT sampled for any species by my group of interest (e.g., genes that are specific to that group of organisms).

I tried this code but it's actually yielding a list of files that DO match for my regexp.
Code:

for FILENAME in *.fas
do
grep -q -L ">PBAH" $FILENAME && grep -q -L ">SKOW" $FILENAME && grep -q -L ">CGRA" $FILENAME && echo $FILENAME
done

Basically I want to somehow go through and file files that do not contain ">PBAH" ">SKOW" or ">CGRA". Any assistance would be greatly appreciated!

Best,
Kevin

I've been using this a lot:

find <directory to start search at> -name "<files to search in>" -type f | xargs grep "<string to search for>"

e.g.

find /usr/include -name "*.h" -type f | xargs grep "#define UINT"

now what if I wanted to output the results to a file?

I want to And search grep shell

but It's hard to grep variable


---------------------------------------------------------------
#!/bin/bash


if [ $# -eq 0 ]
then
echo "Ussage: phone searchfor [...searchfor]"
echo "(You didn't tell me what you want to search for )"

else

pass=0
find=""

for idx in $*
do
if [ -n "$idx" ]
then
if [ $pass -eq 0 ]
then
find=$(egrep "$idx" mydata)
pass=1

else

find=$("$find" | grep "$idx")

echo $find
fi
fi

done

if [ -z "$find" ]
then
echo "There is no such thing"
else

echo $find | awk -f display.awk

fi

fi

-----------------------------------------------------

there is one error : command not found

in find=$("$find" | grep "$idx")

how can I grep variable and store it into variable?

I have install vsftpd and start it , but when when to try it by "ftp localhost" , but not work , would advise what is wrong ? thanks


#ps -ef |grep ftp
Code:

root     29896     1  0 10:53 ?        00:00:00 /usr/sbin/vsftpd /etc/vsftpd/vsftpd.conf
root     29899 23821  0 10:53 pts/0    00:00:00 grep ftp

# ftp localhost
Code:

Connected to localhost (127.0.0.1).
421 Service not available.