Check If Files Exists

Hello,

They gave me this:
Code:

#!/bin/bash

# Write error message on stderr and die
function die() {
  echo "$@" >&2
  exit 1
}

# Load var from properties files
function load() {
  for propertie in "$@" ; do
    [[ -f "${propertie}" ]] || die "load() : \"${propertie}\" don't exist !"
    while read ; do
echo "${REPLY%=*}"
echo "${REPLY#*=}"
      [[ -n "${REPLY%%=*}" && -z "${REPLY#*=}" ]] || die "load() : Variable \"${REPLY%%=*}\" is empty!"
      eval "${REPLY%%=*}"=\'"${REPLY#*=}"\'
    done < "${propertie}"
  done
}

load "manage_srcds.conf"
echo "SRCDS_TICKRATE=$SRCDS_TICKRATE"
echo "SRCDS_SCREEN=$SRCDS_SCREEN"
echo "SRCDS_SRCDS_GAME_NAME=$SRCDS_GAME_NAME"
echo "SRCDS_MAXPLAYERS=$SRCDS_MAXPLAYERS"

but, return:
Quote:
###################################################
###################################################
load() : Variable "###################################################" is empty!

cat manage_srcds.conf

I just wish that there was no empty variable excluding those who do not have integer.

Best regards,

I am trying to check if all three mountpoint commands return true. However when I run the bash script I get a binary operator expected error.

if [[ mountpoint -q /mnt/foo1 && mountpoint -q /mnt/foo2 && mountpoint -q /mnt/foo3 ]]
then
echo "all three true"
else
echo "all three not true"
fi

Hi All..

I need to give four lines of gap(Freespace) between two command outputs.

what i did was below

Code:

echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
print "***************** LEVEL 2: Truncating  Tables: Success:  tables Truncated ***********************" >> $LOG/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
# Run the load scripts.
echo "***************** LEVEL 3: Loading Dupe Check Tables: Success: Dupe Check tables Loaded***********************" >> $LOG/$LOG_NAME

Is there any better way of writing this command to leave multiple lines between two commands.

Please advise...

I am writing a script to check whether a "sysinfo" is installed in a system or not. sysinfo is a tool that gives information about the system. Its is installed in /usr/local/bin. so at CLI when I type sysinfo, it will display output.

#!/bin/bash
sysinfo=`/usr/local/bin/sysinfo`
echo "$sysinfo"
if [ "$?" = 0 ];then
echo "sysinfo installed"
else
echo "Please install sysinfo"
fi

Concept is, I run the command if it is present, it will show output and exit status of command is 0 else it is not installed. But it is not working as expected. Any thoughts , idea, suggestion.

Hi guys,

i'm beginner with Unix, I tried my best, but I Really don't know how to finish it .

here's my problem : I have to do something like Student system - student's name | subjects | mark |credits.

after starting script it will ask you for Student's name, then which subject, then the mark will appear.

It's a homework, and I have my own idea how to solve it, but cannot finish it, i don't want complete solution, just a help!

Code:

#!/bin/bash
echo "Students name"
echo -n "Enter student's name: "
read name
echo
case $name in
Example1|Math) echo "C" ;;
Example2|Programming) echo "D" ;;
Example3|WWW) echo "A" ;;
Example4|Economie) echo "-" ;;
esac

I don't now how to bring together case with second things which is "enter subject".

I appreciate any help

Hello all,

I am trying to figure out how to get bash to view for any contents in the "the_difference_between_today_and_yesterday.txt" file and then act if there is anything in the file. I thought i had it, but it is not working like I thought. Any ideas?

Code:

if [ -f final_version_$dater.txt ];
then
        if [ -f final_version_$yester_dater.txt ];
        then
                diff final_version_$dater.txt final_version_$yester_dater.txt | grep "^>" | sed 's/>\ //g' > the_difference_between_today_and_yesterday.txt

                        if grep ^[a-z]* "the_difference_between_today_and_yesterday.txt";
                        then
                                cp the_difference_between_today_and_yesterday.txt /tmp/24hourlemons_table; mysqlimport --user=USERNAME --password=PASSWORD --columns=name,start_date,end_date,link_url,location \
--fields-terminated-by=':' --lines-terminated-by='\n' carshows /tmp/24hourlemons_table; rm final_version_$three_days_later.txt
                        else
                                echo "There were no differences between the two files"; rm final_version_$three_days_later.txt
                        fi
        else
                echo "ERROR! The file of: final_version_$yester_dater.txt does not exist" >> error.log
        fi
fi

I want to And search grep shell

but It's hard to grep variable


---------------------------------------------------------------
#!/bin/bash


if [ $# -eq 0 ]
then
echo "Ussage: phone searchfor [...searchfor]"
echo "(You didn't tell me what you want to search for )"

else

pass=0
find=""

for idx in $*
do
if [ -n "$idx" ]
then
if [ $pass -eq 0 ]
then
find=$(egrep "$idx" mydata)
pass=1

else

find=$("$find" | grep "$idx")

echo $find
fi
fi

done

if [ -z "$find" ]
then
echo "There is no such thing"
else

echo $find | awk -f display.awk

fi

fi

-----------------------------------------------------

there is one error : command not found

in find=$("$find" | grep "$idx")

how can I grep variable and store it into variable?

Hello everyone,

I recently started using "function" and "case" in linux but I came across a slight problem

My code:

Code:

function Return
{
echo $1
}

case "$1" in 
 ""       ) echo "give parameters please";;
 [0-9]*   ) echo "No numbers please";;
 *        ) Return;;

So whenever the first parameter is a simple word I would like it returned, but it seems like there is no returned string (empty space)

Also I know I can just write "echo $1" instead of Return, but I'd like to use a function for this.

Can anyone tell me why the function doesn't return $1? Thanks!

i need to complete this exercise but my code has some issues
HERE is the PRoblem:
Create a script that can accept ANY amount of numbers from the command line. Process the numbers one at a time, where numbers greater than 10 print “large”, numbers less than or equal to 10 print “small”
E.g. process 5 10 15 would print
small
small
large

and here is my code so far
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi

any help would be greatly appreciated

Hi all,

I am trying to write a script that syncs files from source to destination. I have one centralized server that can ssh to any servers without pw. Now when I run the script, it can ssh to source server perfectly fine, but you need to enter password for destination server. Was wondering how I can clean this up before I start using case statements

Below is a sample I wrote

#!/bin/bash

#This scripts syncs shit

echo "Type in ID: "
read ID

echo "Type in Server : " #source server
read S

echo "Type in Destination Server: "
read DS

if [ $S == 9 ]; then
ssh -t "root@"$S"webserver1" "rsync -av /home/rlui/"$ID "root@"$DS"webserver2:/home/rlui/";
ssh -t "root@"$S"webserver1" "rsync -av /home/rlui/tmp/"$ID "root@sl"$DS"webserver2:/home/rlui/tmp/"
exit 1

where S and DS are cluster numbers

I apologize in advance if I am not clear on anything