Parameter $1 Isn't Returned After A Case (bash Scripting)

Hello,

They gave me this:
Code:

#!/bin/bash

# Write error message on stderr and die
function die() {
  echo "$@" >&2
  exit 1
}

# Load var from properties files
function load() {
  for propertie in "$@" ; do
    [[ -f "${propertie}" ]] || die "load() : \"${propertie}\" don't exist !"
    while read ; do
echo "${REPLY%=*}"
echo "${REPLY#*=}"
      [[ -n "${REPLY%%=*}" && -z "${REPLY#*=}" ]] || die "load() : Variable \"${REPLY%%=*}\" is empty!"
      eval "${REPLY%%=*}"=\'"${REPLY#*=}"\'
    done < "${propertie}"
  done
}

load "manage_srcds.conf"
echo "SRCDS_TICKRATE=$SRCDS_TICKRATE"
echo "SRCDS_SCREEN=$SRCDS_SCREEN"
echo "SRCDS_SRCDS_GAME_NAME=$SRCDS_GAME_NAME"
echo "SRCDS_MAXPLAYERS=$SRCDS_MAXPLAYERS"

but, return:
Quote:
###################################################
###################################################
load() : Variable "###################################################" is empty!

cat manage_srcds.conf

I just wish that there was no empty variable excluding those who do not have integer.

Best regards,

Hi guys,

i'm beginner with Unix, I tried my best, but I Really don't know how to finish it .

here's my problem : I have to do something like Student system - student's name | subjects | mark |credits.

after starting script it will ask you for Student's name, then which subject, then the mark will appear.

It's a homework, and I have my own idea how to solve it, but cannot finish it, i don't want complete solution, just a help!

Code:

#!/bin/bash
echo "Students name"
echo -n "Enter student's name: "
read name
echo
case $name in
Example1|Math) echo "C" ;;
Example2|Programming) echo "D" ;;
Example3|WWW) echo "A" ;;
Example4|Economie) echo "-" ;;
esac

I don't now how to bring together case with second things which is "enter subject".

I appreciate any help

i need to complete this exercise but my code has some issues
HERE is the PRoblem:
Create a script that can accept ANY amount of numbers from the command line. Process the numbers one at a time, where numbers greater than 10 print “large”, numbers less than or equal to 10 print “small”
E.g. process 5 10 15 would print
small
small
large

and here is my code so far
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi
if [ $@ -le "10" ]
then
echo "smaller"
else
echo "bigger"
shift
fi

any help would be greatly appreciated

Code:

PREFIX=192.168.1
OCTET=1
while [ $OCTET -lt "255" ]; do
    echo -en "Pinging ${PREFIX}.${OCTET}..."
    ping -c1 -w1 ${PREFIX}.${OCTET} > /dev/null 2>&1
    if [ "$?" -eq "0" ]; then
       echo "OK"
    else
       echo "Failed"
    fi
    let OCTET=$OCTET+1
done

My question is, in the penultimate line, why is it OCTET, and not $OCTET, with a dollar before it, meaning, the variable?

What if it were written:
Code:

let $OCTET=$OCTET+1

Like in C++ (I think) or Python or whatever?

I want to create a simple bash function (in .bashrc) that takes in one parameter (a directory name) and tars all the files inside of that directory into a specific directory in /home (we'll call that destdir). The name of the tar should be the same as the directory parameter.

For example, I want to be able to type into the terminal "task directory_name".

I tried this but it didn't work:

Code:

function_name() {
   cd $1
   tar czf /~/destdir/$1.tar *

   return 0
}
alias task=function_name

What am I doing wrong?

hi
I try to assign return from a _error_handler_function to a variable
this is just a test( dummy test ) not a really case


#!/bin/bash
logfile="/dev/shm/log.err"
exec 2>$logfile
_err_handler(){
v=$(cat $logfile|grep dummy|wc -l);
rm $logfile
echo $v
}

trap _err_handler ERR

x=$(dummy);
echo "x value is $x "
z=$(notrap)
echo "z value is $z"


expected output :
bash-4.1$ sh test2.sh
x value is 1
z value is 0


what is wrong here and how should I fix?

thanks in advance

Hi All..

I need to give four lines of gap(Freespace) between two command outputs.

what i did was below

Code:

echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
print "***************** LEVEL 2: Truncating  Tables: Success:  tables Truncated ***********************" >> $LOG/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
echo "" >>$LOG_DIR/$LOG_NAME
# Run the load scripts.
echo "***************** LEVEL 3: Loading Dupe Check Tables: Success: Dupe Check tables Loaded***********************" >> $LOG/$LOG_NAME

Is there any better way of writing this command to leave multiple lines between two commands.

Please advise...

Hi all,

I am trying to write a script that syncs files from source to destination. I have one centralized server that can ssh to any servers without pw. Now when I run the script, it can ssh to source server perfectly fine, but you need to enter password for destination server. Was wondering how I can clean this up before I start using case statements

Below is a sample I wrote

#!/bin/bash

#This scripts syncs shit

echo "Type in ID: "
read ID

echo "Type in Server : " #source server
read S

echo "Type in Destination Server: "
read DS

if [ $S == 9 ]; then
ssh -t "root@"$S"webserver1" "rsync -av /home/rlui/"$ID "root@"$DS"webserver2:/home/rlui/";
ssh -t "root@"$S"webserver1" "rsync -av /home/rlui/tmp/"$ID "root@sl"$DS"webserver2:/home/rlui/tmp/"
exit 1

where S and DS are cluster numbers

I apologize in advance if I am not clear on anything

Hi,

I am new to UNIX - i wrote this below script based on the requirement. But i am stuck at the concatenation (at the second last step of the code)

The below code is working fine till the concatenation(second last step) - I need to concatenate Hello to the "physId" e.g. - The filename is UM123456789.20150503 - i am extracting M123456789 and i need to append "HELO" to it at the end. But as per the below script - when i am using the concatenation, it is overwriting the M123456789 and the output thus becomes HELO456789. I am trying to get the output as - M123456789HELO - where am i going wrong?

on the terminal i checked - echo $0 and it gave -> /bin/sh. Hence i wrote the below code.

#!bin/sh
absolutePath=/abc/data/abc_unix/stg/decrypt/*.*
filepath=$(echo ${absolutePath%.*})
echo "$filepath"
filenameext=$(echo ${filepath#/abc*decrypt/})
echo "$filenameext"
file=$(echo ${filenameext#.*})
echo "$file"
extract_physId=$(echo ${file:1:9})
physId=$(echo ${extract_physId})
echo "$physId"
key="$physId"HELO
echo "$key"

I use following shell script to send email. But the subject of email always shows "This" instead of "This is L_1.R is finished". You may refer http://www.linuxquestions.org/questions/linux-newbie-8/how-to-define-variable-in-%60ssh%60-4175540566/
Code:

host_list=("c15-0330-01.ad.mtu.edu" "c15-0330-02.ad.mtu.edu" "c15-0330-03.ad.mtu.edu" "c15-0330-04.ad.mtu.edu")
program=("L_1" "L_2" "L_3" "L_4")
subject="The job is finished"
ssh -f c15-0330-01.ad.mtu.edu 'echo' "the job ${program[0]} is finished" '|' 'mutt "zwang10@mtu.edu" -s' "This is "${program[0]}".R is finished";