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How To Use Static Libraries? Please Help Lol

https://code.google.com/p/wavelet1d/...ar.gz&can=2&q=

The above link is where I downloaded *.cpp(s) and the libraries.

If you "untar" the package, in "examples" directory, there are some demonstration files. What I wanted to do was to make an executable file out of "wavedemo1.cpp".

I modified the code in "wavedemo1.cpp"; Code:

#include "wavelet2d.h"

to Code:

#include "wavelet2s.h"

, then placed the header file "wavelet2s.h" (from /wavelib/src/linuxstatic) and the modified "wavedemo1.cpp" into my working directory.

Inside the working directory, I ran the following command

Code:

gcc -L/home/mario/wavelet/wavelib/linuxstatic -lwavelet2s wavedemo1.cpp -o wavedemo1

Then I get the following error messages.

/usr/bin/ld: skipping incompatible /home/mario/wavelet/wavelib/linuxstatic/libwavelet2s.a when searching for -lwavelet2s
/usr/bin/ld: cannot find -lwavelet2s
collect2: error: ld returned 1 exit status

I'm not sure what went wrong with my approach. This is my first time trying to use libraries on linux and it's giving me really tough times.

I would appreciate your help, please let me know if you need more details to explain things.

Thanks.

Problem With (instalation Of?) Mysql.h On C

Hi, I've just recently installed MySQL connector/c from source code on my Slackware 14.1 x64

I read the official instructions of the connector but I felt a bit disorientated when I read:
Code:

1 -Change location to the top-level directory of the source distribution.

I interpreted that I have to go to the "highest" directory Code:

So I wrote: Code:

 
        #                            cd /

root@- /#                            tar xzvf /home/normal/Downloads/mysql-connector-c-6.1.6-src.tar.gz 

root@- /#                            cd /mysql-connector-c-6.1.6-src/

root@- /mysql-connector-c-6.1.6-src# cmake -G "Unix Makefiles"

root@- /mysql-connector-c-6.1.6-src# make 

root@- /mysql-connector-c-6.1.6-src# make install

Then I did:
Code:

ln -s /usr/local/mysql-5.6.25/include /usr/include

But when I try to compile a program in c with #include <mysql.h> i get this error:
Code:

# gcc ctemp.c 
In file included from ctemp.c:2:0:
/usr/include/mysql.h:57:27: fatal error: mysql_version.h: No such file or directory
 #include "mysql_version.h"
                           ^

What can I do? Thanks a lot and sorry for poor english

PD: If you need the official instructions I paste here the link: https://dev.mysql.com/doc/connector-...on-source.html

Python Ftplib

hello all,

please help me with python ftplib. i was trying to copy files from my linux machine to a windows server using ftplib. everything was working good. but i'm only able to copy files from the same directory the script is. how do i copy files from a different directory? i always get "file not found error message". here's my code :

Code:

tester_name = str (socket.gethostname())
def upload(ftp, file):
    ext = os.path.splitext(file)[1]
    if ext in (".txt", ".htm", ".html"):
        ftp.storlines("STOR " + file, open(file))
    else:
        ftp.storbinary("STOR " + file, open(file, "rb"), 1024)



parse_source_path = ('/path/to/where/i/go/')
parse_source_file_list = os.listdir(parse_source_path)

ftp = ftplib.FTP("server_IP")
ftp.login("username", "pass")

folder_list = []

ftp.dir(folder_list.append)

if str(tester_name) not in str(folder_list) :
    ftp.mkd("%s"%tester_name)
    ftp.cwd("%s"%tester_name)
    for files in parse_source_file_list :
        print files
        upload(ftp, files)


else :
    print "later"

Duplicate Folder Creation While Using Mkdir In A Script

Hello,

I am setting up a linux server for gaming and I am using a script to update the files automatically and create a folder with a certain name.

Code:

# !/bin/bash

# A convenience function, to save us some work
update_server() {
	# Read the app id and the directory into a variable

	APP_ID=$1
	DIR=$2

	# Create the directory ( if it does not exist already )
	if [ ! -d "$HOME/$DIR" ]; then
		mkdir -p "$HOME/$DIR"
	fi

	# Uh-oh, it looks like we still have no directory. Report an error.
	if [ ! -d "$HOME/$DIR" ]; then
		# Describe what went wrong
		echo "ERROR! Cannot create directory $HOME/$DIR!"

		# Exit with status code 1 ( which indicates an error )
		exit 1
	fi

	# Call SteamCMD with the app ID we provided and tell it to install
	./bin/steamcmd.sh +login anonymous +force_install_dir "$HOME/$DIR" +app_update $APP_ID validate +quit
}

# Now the script actually runs update_server ( which we just declared above ) with the id of the application ( 4020 is Garry's Mod ) and the name of the directory we want the server to be hosted from:

update_server 4020 "gmodserver"

exit 0

When I run this script, it creates 2 folders on my server : gmodserver and gmodserver? There is no files downloaded in gmodserver. All the files are downloaded in gmodserver?

I looked for a few hours on how to solve this problem but I have no idea what the added ? might be so I am lost as to what to look for. Could you help me on figuring this out?

Thank you.

edit : I am using ubuntu 15.04 x64 if it makes a difference.

What Does The "T" Mean When You List File Permissions W/ Ls -l

I have a directory w/ a file that I created using:
Code:

fd = open("file", O_CREAT);

The file turned out to be executable. When I did a 'ls -l' on the directory w'/ that file it has a "T" at the end of the permissions where the executable bit would be set for the "other" group.

Rsync, Reliable "copy And Paste" Type Of Backup In Case Things Break?

What I did in windows was create images of my drive and restore them.

in linux I am running

Code:

rsync -aAXv --exclude={"/home/*","/dev/*","/proc/*","/sys/*","/tmp/*","/run/*","/mnt/*","/media/*","/lost+found"} /* /path/to/backup/folder

and this creates a folder for me with all my files, and apparently saves meta data like permissions and paths...

Since I'm using arch and things break sometimes,I'm booted into a CLI with errors and cannot figure my way out since I'm a noob... would I be able to just delete my entire root and replace it with the rsync backup without a problem?

"vconsole.conf" Show Unicode

Hi!

Here is mine configuration and I want make it show unicode(russian) in console, it works perfect in X11 but not when I logging into tty.

vconsole.conf
Code:

LOCALE="en_US.UTF-8"
KEYMAP="sv-latin1"
FONT_UNIMAP="lat1"
FONT_MAP="ISO8859-1"
CONSOLEFONT="ruscii_8x8"
HARDWARECLOCK="localtime"
TIMEZONE="Europe/Stockholm"
USECOLOR="yes"

Why Should I Always Use Chmod When Not As A Root User

System Info:

I have normal user in CentOS 7 whose name is "mostafa" (the name of the account).

I naturally have another user called root with all privileges. User "mostafa" is put into sudoers file, too.

The OS is installed in VmWare, so the system is all mine.

Problem:

Now I create a file with touch file.sh and put a command in it, but when I want to run it with Code:

sudo ./file.sh

, an error is shown that the command Code:

./file.sh

does not exist. But if I Code:

 sudo chmod 777 ./file.sh

then it gets run. My question is that, why should I use Code:

chmod 777

when I myself have created the file, and I am in sudoers.

Can anyone explain me why shuold I still use Code:

sudo chmod 777

when the creator of the file is me.

Mutt Does Not Show Full Subject

I use following shell script to send email. But the subject of email always shows "This" instead of "This is L_1.R is finished". You may refer http://www.linuxquestions.org/questions/linux-newbie-8/how-to-define-variable-in-%60ssh%60-4175540566/
Code:

host_list=("c15-0330-01.ad.mtu.edu" "c15-0330-02.ad.mtu.edu" "c15-0330-03.ad.mtu.edu" "c15-0330-04.ad.mtu.edu")
program=("L_1" "L_2" "L_3" "L_4")
subject="The job is finished"
ssh -f c15-0330-01.ad.mtu.edu 'echo' "the job ${program[0]} is finished" '|' 'mutt "zwang10@mtu.edu" -s' "This is "${program[0]}".R is finished";

Parameter $1 Isn't Returned After A Case (bash Scripting)

Hello everyone,

I recently started using "function" and "case" in linux but I came across a slight problem

My code:

Code:

function Return
{
echo $1
}

case "$1" in 
 ""       ) echo "give parameters please";;
 [0-9]*   ) echo "No numbers please";;
 *        ) Return;;

So whenever the first parameter is a simple word I would like it returned, but it seems like there is no returned string (empty space)

Also I know I can just write "echo $1" instead of Return, but I'd like to use a function for this.

Can anyone tell me why the function doesn't return $1? Thanks!

Basic Bash Script

Code:

PREFIX=192.168.1
OCTET=1
while [ $OCTET -lt "255" ]; do
    echo -en "Pinging ${PREFIX}.${OCTET}..."
    ping -c1 -w1 ${PREFIX}.${OCTET} > /dev/null 2>&1
    if [ "$?" -eq "0" ]; then
       echo "OK"
    else
       echo "Failed"
    fi
    let OCTET=$OCTET+1
done

My question is, in the penultimate line, why is it OCTET, and not $OCTET, with a dollar before it, meaning, the variable?

What if it were written:
Code:

let $OCTET=$OCTET+1

Like in C++ (I think) or Python or whatever?

How To Use Static Libraries? Please Help Lol

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