File Searching In Log

I have a Kubuntu install that works fine but for some reason, it grows the logs into hundreds of GBs.

Is there a method to prevent those logs from growing so large? I researched "log rotate" but I couldn't understand it.

I would like something established such that after a certain size, the logs are automatically deleted so I don't have to do it manually each time.

How would I do so?

Here are the logs:

#1: /var/log/syslog
#2: /var/log/kern.log

I already determined I don't need them, so I would like to auto-delete them once they reach a certain size.

Thank you.

hi experts

I am running a large rsync job, but the exclude list doesn't seem to be working:

The rsync log shows this file as being copied over
/a/test 4.11/Logs/2015-03-03_PID_1234/x.y

but the exclude file clearly includes this line:
/a/test*/Logs/*PID*

So shouldn't it have been excluded?
Thanks

hi,

I am newbie in Linux shell scripting.Can anybody help me to check the presence of file identified by variable in Shell scripting?

For example: I am reading the content of a file using while command as below:
"while read -r line
do
code block
done < file_name"

Now in this case every line in file gets stored in the variable 'line' one by one.Problem here is every line in the file is nothing but the file_path of another file say xyz.txt and I am checking presence of this xyz.txt file using below command:
if [-f $line]
as 'line' is the variable which stores file path of xyz.txt but it is not working. It is unable to check the presence of this xyz.txt file as i am addressing it with the variable 'line'.

Please help me.Thanks in advance.

I have two files which has exact same number of lines.
I want first line of first file should be filename of new file and content of this new file should be first line of second file.
Then second line of first file should be filename of again new file and content of this new file should be second line of second file.
then third line of first file should be filename of again new file and content of this new file should be third line of second file.
and so on...
I am trying to do it using for loop but I am not able to create two for loops.
This is what I have done
Code:

IFS=$'\n'
var=$(sed 's/\"http\(.*\)\/\(.*\).wav\"\,\".*/\2/g' 1797.csv) # filenames of all files
var2=$(sed 's/\"http\(.*\)\/\(.*\).wav\"\,\"\(.*\)\"$/\3/g' 1797.csv) # contents of all files
for j in $var;
do
#Here I do not know how to use $var2
done

Please help.

hey there
And again, I got stuck in this problem.
I could not find honeyd logs in var/logs/honeypot/
there isnt any file.

I ran the honeyd with "honeyd -d -f honeyd.conf"
it works in terminal. but there arent any logs at all.

root@kali:/etc/honeypot# honeyd -d -f honeyd.conf
Honeyd V1.5c Copyright (c) 2002-2007 Niels Provos
honeyd[6952]: started with -d -f honeyd.conf
honeyd[6952]: listening promiscuously on eth0: (arp or ip proto 47 or (udp and src port 67 and dst port 68) or (ip )) and not ether src 98:4b:e1:94:62:46
honeyd[6952]: [eth0] trying DHCP
honeyd[6952]: Demoting process privileges to uid 65534, gid 65534
honeyd[6952]: [eth0] got DHCP offer: 192.168.23.3
honeyd[6952]: Updating ARP binding: 00:00:24:8b:83:c3 -> 192.168.23.3
honeyd[6952]: arp reply 192.168.23.3 is-at 00:00:24:8b:83:c3
honeyd[6952]: Sending ICMP Echo Reply: 192.168.23.3 -> 110.44.116.18

after some research, i came to know that i should include "-l" to create logs.
but it showed me only this.

root@kali:/etc/honeypot# honeyd -l -d -f honeyd.conf
Honeyd V1.5c Copyright (c) 2002-2007 Niels Provos
honeyd[6960]: started with -l -d -f honeyd.conf
honeyd[6960]: listening promiscuously on eth0: (arp or ip proto 47 or (udp and src port 67 and dst port 68) or (ip )) and not ether src 98:4b:e1:94:62:46
honeyd[6960]: [eth0] trying DHCP
Honeyd starting as background process
root@kali:/etc/honeypot#

so what could be the issue? Urgent help needed.
thanks in advance
P.S I am a linux newbie.

Hi Linux Guru's

just want to ask any keyword on hardware logs that show's the box shut downs it self

I'm using CentOS release 6.4 (Final)

Hi ,

i am working in linux last 6 month. and i want to now that i have a apache server and some one has change some line in httpd.conf yesterday or day before yesterday how i know what change was done in this file on which date.anyone can help


Regards
Charles

Hi all ,
I have a requirement where I have a file. Contents of the file are :
#comments
VAR="abg"
RES=123
#comments
IC6790ABG="https://www.abc.com"
IC5678-vg="https://www.bhy.com"
IC-gy_567:78="https://www.gyt.com"
#comments
The variable names can not have characters like - , : so
in this file I have to find words starting with IC and replace characters like - ,:
I want to change only the variable name , not the whole line.
I have used SED command

sed -i '/^IC/s/[^0-9 a-z A-Z _]*//g' file

when I am using this command , it is replacing the whole line
output becomes :

#comments
VAR="abg"
RES=123
#comments
IC6790ABGhttpswwwabccom
IC5678vghttpswwwbhycom
ICgy56778httpswwwgytcom
#comments


But I want the output like this :

#comments
VAR="abg"
RES=123
#comments
IC6790ABG="https://www.abc.com"
IC5678vg="https://www.bhy.com"
ICgy_56778="https://www.gyt.com"
#comments

How can I get the desired output , thanks for your help in advance .

I would like to tar up some system logs with core files as a normal user through a script. However these core files are owned by root.

Of course I get "cannot read directory ...: Permission denied"

Is there a good way to grab these core files through a script? From searching around, I get that the best way is to modify the sudoers file, then run the script with sudo. Is this considered the safest and best way?

Thanks!

When working with a virtual terminal, I find it often easier to edit a file to execute than to construct a regular-expression etc. to inject the right UUID etc. into the command. I have run into an error while doing this. I suspect it is stems from quote mishandling, or improper escape sequences. (I ran directly from the command line earlier, forgot a quotation mark, and it gave a similar bad result.)
The program in question was efibootmgr. I had a file vaguely similar to this one, named efiboot.Hz:
Code:

efibootmgr -c -g -L "Debian (EFI stub)" -l '\EFI\debian\vmlinuz' -u 'root=UUID=$UUID ro quiet rootfstype=ext4 add_efi_memmap initrd=\\EFI\\debian\\initrd.img'
efibootmgr -c -d /dev/sdb -L "Debian Linux" -l '\EFI\debian\vmlinuz' -u 'root=UUID=1234-ffff-789 ro quiet rootfstype=ext4 add_efi_memmap initrd=\\EFI\\debian\\initrd.img'

Then I executed:
Code:

`tail -n 1 efiboot.Hz`

efibootmgr -v revealed the previous command produced a garbled name and boot options, and most importantly it didn't boot. Manually writing the last line on the terminal did produce the desired effect. I thought I checked the output from tail before putting the back-ticks.
What did I do wrong?